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alexira [117]
2 years ago
13

Which is a zero of the function f(x)=3x−12?

Mathematics
1 answer:
N76 [4]2 years ago
3 0
<h3>Answer:  x = 4</h3>

==================================================

Explanation:

Replace f(x) with 0 and solve for x.

f(x) = 3x-12

0 = 3x-12

3x-12 = 0

3x = 12

x = 12/3

x = 4 is a zero, aka root, of the function

---------------

Check:

f(x) = 3x-12

f(4) = 3(4)-12

f(4) = 12-12

f(4) = 0

The answer is confirmed.

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Need help on both of these for geometry
artcher [175]

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Step-by-step explanation:

have the triangles written in the same order to se the corresponding angles

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4 0
2 years ago
D)) The ratio of the monthly income and expenditure of Sunayana is 5 : 3. If she
Gnom [1K]

Answer:

Sunayana's income is ₹25000 and expenditures are ₹15000.

Step-by-step explanation:

Let i denote the monthly income and e denote the expenditures.

We know that the ratio of the monthly income to expenditure is 5:3. So, we can write the following proportion:  

\frac{i}{e}=\frac{5}{3}

Let's multiply both sides by e. This yields:

i=\frac{5}{3}e

We know that when the income is <em>increased</em> by 5000 and the expenditures are <em>decreased </em>by 3000, the new ratio is 5:2. So, we can write the following proportion:

\frac{i+5000}{e-3000}=\frac{5}{2}

Let's multiply both sides by (e-3000):

i+5000=\frac{5}{2}(e-3000)

Since we know that i=\frac{5}{3}e, substitute:

\frac{5}{3}e+5000=\frac{5}{2}(e-3000)

So, let's solve for the expenditures. Distribute the right:

\frac{5}{3}e+5000=\frac{5}{2}e-7500

Subtract \frac{5}{2}e from both sides:

-\frac{5}{6}e+5000=-7500

Subtract 5000 from both sides:

-\frac{5}{6}e=-12500

Multiply both sides by -6/5. So, the expenditures are:

e=\text{Rs }15000

We can use the original ratio to find Sunayana's income:

i=\frac{5}{3}e

Substitute 15000 for e. Evaluate:

i=\frac{5}{3}(15000)=\text{Rs }25000

So, Sunayana's income is ₹25000 and expenditures are ₹15000.

And we're done!

Edit: Wrong currency, sorry about that!

3 0
3 years ago
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