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7. Okay. So the computer was originally $1,080, and the discount is 20%, but David would still have to pay 80% of the original price. To find the sale price, let's multiply. 1,080 * 80% (0.8) is 864. The sale price of the compuet is $864, but now we must add the sales tax to find the total price. We will multiply by 108%, because 100% (representing the price + 8% is 108%, and doing this will get us stright to the total price. 864 * 108% (1.08) is 933.12. There. David paid a total price of $933.12 for the computer.
8. Okay. So we are looking for the amount of discount for the sweater Suzanne bought. First off, let's subtract the prices to find the difference. 40 - 25 is 15. Now, let's divide that by 40 (the original price) to find the discount. 15/40 is 0.375. Or 37.5% when converted into a percentage. There. Suzanne received a 37.5% discount on the sweater when she bought it.
9. So the car was bought for x dollars. 0.88 represents 88%, so the value of the car is 88% of the previous year. An expression that is a way to describe the change in car value is x * (100 - 0.12)^t, because you car loses 12% of the remaining value each year, which leaves 88% of it remaining, and having the t as the exponent represents the number of years. That expression helps find the value of the car currently and can help you compare the values.
Your goal is to have x by itself
Send st to other side
rx= r+st
Divide by r so x stays alone
X=(r+st)/r
Which is also equal to
X=r/r+st/r
X= 1+st/r
Answer:

Step-by-step explanation:
The formula for the length of a vector/line in your case.
![L = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} = \sqrt{[4 - (-1)]^2 + [2 -(-3)]^2} = \sqrt{5^2 + 5^2} = \sqrt{50} = 5\sqrt{2}](https://tex.z-dn.net/?f=L%20%3D%20%5Csqrt%7B%28x_2-x_1%29%5E2%20%2B%20%28y_2-y_1%29%5E2%7D%20%3D%20%5Csqrt%7B%5B4%20-%20%28-1%29%5D%5E2%20%2B%20%5B2%20-%28-3%29%5D%5E2%7D%20%3D%20%5Csqrt%7B5%5E2%20%2B%205%5E2%7D%20%3D%20%5Csqrt%7B50%7D%20%3D%205%5Csqrt%7B2%7D)
The <em>correct answer</em> is:
The median is less than the mean.
Explanation:
This histogram is skewed right; the data "peaks" further to the left than the center.
If a histogram is skewed right, the mean is greater than the median.
This is because skewed-right data have a few large values that increase the mean but do not affect where the exact middle of the data is.

- How do you simplify this?
- x²y+xy² / y²+2/5 × xy


Factor the expressions that are not already factored.
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<u>How </u><u>to</u><u> factorise</u><u> </u><u>:</u><u>-</u>
<u>NUMERATOR</u> 

Factor out xy.

<u>DENOMINATOR</u> 

Factor out 1/5.

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Continuing...

Cancel out y in both the numerator and denominator.

Expand the expression.

This can further simplified to as 
