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3 years ago

6/2(1+2)+1-1+1-1+1-1

Mathematics

2 answers:

ValentinkaMS [17]3 years ago

8 0

= 6/2*(1+2)+1-1+1-1+1-1

= 6/2*(3)+1-1+1-1+1-1

= 6/2*3+1-1+1-1+1-1

= 3*3+1-1+1-1+1-1

= 9+1-1+1-1+1-1

= 10-1+1-1+1-1

= 9+1-1+1-1

= 10-1+1-1

= 9+1-1

= 10-1

= 9

elixir [45]3 years ago

7 0

SO do the one in the paranthesis first.

First we need to add the paranthesis. Which we will get 3.

3*2 ( because multiply goes first). Then divide the number 6 with the conclusion of 1. Then as we add and subtract 1, we will get the answer 1!

Answer : 1!

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Taylor buys 2 gallons of milk for $5.50. What is the cost per gallon

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Answer:

its 2.75 for one gallon

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3 years ago

Given f(x) = 2(4 – x)2, what is the value of F(15)? Record your answer and fat in the bubbles on your anser document

kari74 [83]

Answer:

f(15) = 242

Step-by-step explanation:

Step 1: Define

f(x) = 2(4 - x)²

f(15) = x = 15

Step 2: Substitute and Evaluate

f(15) = 2(4 - 15)²

f(15) = 2(-11)²

f(15) = 2(121)

f(15) = 242

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3 years ago

What congruent theorem is this triangle...need help please

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3 years ago

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Andre45 [30]

Answer:

$a_n=-3(3)^{n-1}$ ; {-3,-9, -27,- 81, -243, ...}

$a_n=-3(-3)^{n-1}$ ; {-3, 9,-27, 81, -243, ...}

$a_n=3(\frac{1}{2})^{n-1}$ ; {3, 1.5, 0.75, 0.375, 0.1875, ...}

$a_n=243(\frac{1}{3})^{n-1}$ ; {243, 81, 27, 9, 3, ...}

Step-by-step explanation:

The first explicit equation is

$a_n=-3(3)^{n-1}$

At n=1,

$a_1=-3(3)^{1-1}=-3$

At n=2,

$a_2=-3(3)^{2-1}=-9$

At n=3,

$a_3=-3(3)^{3-1}=-27$

Therefore, the geometric sequence is {-3,-9, -27,- 81, -243, ...}.

The second explicit equation is

$a_n=-3(-3)^{n-1}$

At n=1,

$a_1=-3(-3)^{1-1}=-3$

At n=2,

$a_2=-3(-3)^{2-1}=9$

At n=3,

$a_3=-3(-3)^{3-1}=-27$

Therefore, the geometric sequence is {-3, 9,-27, 81, -243, ...}.

The third explicit equation is

$a_n=3(\frac{1}{2})^{n-1}$

At n=1,

$a_1=3(\frac{1}{2})^{1-1}=3$

At n=2,

$a_2=3(\frac{1}{2})^{2-1}=1.5$

At n=3,

$a_3=3(\frac{1}{2})^{3-1}=0.75$

Therefore, the geometric sequence is {3, 1.5, 0.75, 0.375, 0.1875, ...}.

The fourth explicit equation is

$a_n=243(\frac{1}{3})^{n-1}$

At n=1,

$a_1=243(\frac{1}{3})^{1-1}=243$

At n=2,

$a_2=243(\frac{1}{3})^{2-1}=81$

At n=3,

$a_3=243(\frac{1}{3})^{3-1}=27$

Therefore, the geometric sequence is {243, 81, 27, 9, 3, ...}.

6 0

3 years ago

Find two numbers if there sum is 7.2 and their difference is 2.7

Sidana [21]

Answer:

2.25 and 4.95

Step-by-step explanation:

x + y = 7.2

x - y = 2.7

x = 7.2 - y

x - y = 2.7

(7.2 - y) - y = 2.7

7.2 - 2y = 2.7

-2y = 2.7 - 7.2

-2y = -4.5

-2y/-2 = -4.5/-2

y = 2.25

x + y = 7.2

x + 2.25 = 7.2

x = 7.2 - 2.25

x = 4.95

Check: 4.95 and 2.25

x + y = 7.2

(4.95) + (2.25) = 7.2

7.2 = 7.2

x - y = 2.7

(4.95) - (2.25) = 2.7

2.7 = 2.7

6 0

3 years ago

Read 2 more answers

6/2(1+2)+1-1+1-1+1-1​

6/2(1+2)+1-1+1-1+1-1