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ad-work [718]
2 years ago
10

X • 1/5 = 60 Find out what x represents. Show work.

Mathematics
1 answer:
igor_vitrenko [27]2 years ago
6 0

Answer:

x*1/5=60

5[x*1/5=60]

x=5*60

x=300

Step-by-step explanation:

-introduce the multiplicative inverse of 1/5 to the equation.

- 5*1/5 gives 1 on L.H.S

-Similarly 5*60 gives 300 on R.H.S

-finally x=300

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Answer:21

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Answer:

The correct option is C:

C) The representative sample contained more girls than boys.

Step-by-step explanation:

It is given that a random sample is chosen from a total students of 160 students. The sample can be of 10,15 or any small numbers of students as compared to 160. However, a sample cannot be of 160 students as it is defined as a population in this case.

A random sample is always unbiased. Which means that the sample chosen should have around the same proportion of girls to boys as it is in the population of 160.

We know that:

Total boys in 160 = 65

Total girls in 160 = 95

Proportion of girls to boys = 95/65 = 1.462

Which means that for every 1 boy, there are 1.462 of girls.

The same ratio is held in a random sample, hence the total number of girls will be greater than boys

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3 years ago
"select all the numbers that are solutions to the equation x^3=27"
Ymorist [56]
B and C

3^3 = 27
the cubed root of 27 is 3
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2 years ago
What is the limit in miles per hour if the speed limit is 55 km/hr??
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This problem has been solved!See the answerA municipal bond service has three rating categories (A, B, and C). Suppose that in t
mariarad [96]

Answer:

a. \frac{35}{51}

b. \frac{51}{100}

c. \frac{1}{5}

Step-by-step explanation:

Suppose cities represented by C', suburbs represented by S and rural represented by R,

Let x be the total number of bonds issued throughout the US,

According to the question,

n(A) = 70% of x = 0.7x,

n(B) = 10% of x = 0.1x,

n(C) = 20% of x = 0.2x,

n(A∩C') = 50% of n(A) = 0.5 × 0.7x = 0.35x,

n(A∩S) = 20% of n(A) = 0.2 × 0.7x = 0.14x,

n(A∩R) = 30% of n(A) = 0.3 × 0.7x = 0.21x,

n(B∩C') = 40% of n(B) = 0.4 × 0.1x = 0.04x,

n(B∩S) = 30% of n(B) = 0.3 × 0.1x = 0.03x,

n(B∩R) = 30% of n(B) = 0.3 × 0.1x = 0.03x,

n(C∩C') = 60% of n(C) = 0.6 × 0.2x = 0.12x,

n(C∩S) = 15% of n(C) = 0.15 × 0.2x = 0.03x,

n(C∩R) = 25% of n(C) = 0.25 × 0.2x = 0.05x,

n(C') = n(A∩C')  + n(B∩C')  + n(C∩C')  = 0.35x + 0.04x + 0.12x = 0.51x

n(S) = n(A∩S) + n(B∩S) + n(C∩S) = 0.14x + 0.03x + 0.03x = 0.20x

a. The probability that it will receive an A rating, if a new municipal bond is to be issued by a city,

P(\frac{A}{C'})=\frac{P(A\cap C')}{P(C')}=\frac{0.35x/x}{0.51x/x}=\frac{0.35}{0.51}=\frac{35}{51}

b. The proportion of municipal bonds are issued by cities = \frac{n(C')}{x}

=\frac{0.51x}{x}

=\frac{51}{100}

c. The proportion of municipal bonds are issued by suburbs = \frac{n(S)}{x}

=\frac{0.20x}{x}

=\frac{20}{100}

=\frac{1}{5}

3 0
2 years ago
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