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2 years ago

12

Can you help me please?

1 answer:

Helen [10]2 years ago

5 0

prolly 4.36 just use the Pythagorean theorem

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Suppose u and v are functions of x that are differentiable at x=0 and that u(0)=3, u'(0)= -4, v(0)= 2, v'(0)= -7. Find the value

3241004551 [841]

$\bf \cfrac{d}{dx}[u(x)\cdot v(x)]\implies \cfrac{du}{dx}\cdot v(x)+u(x)\cdot \cfrac{dv}{dx}\quad 
\begin{cases}
u(0)=3\qquad u'(0)=-4
\\\\
v(0)=2\qquad v'(0)=-7
\end{cases}
\\\\
\left[ \cfrac{du}{dx} \right]_{x=0}\cdot v(0)+u(0)\cdot \left[ \cfrac{dv}{dx} \right]_{x=0}$

so.. hmm pretty sure you know what that is

7 0

3 years ago

Read 2 more answers

How to find the slope on a table

bazaltina [42]

M= y2-y1/x2-x1

Make sure you put it in the form

Hope this helps!!:))

5 0

2 years ago

triangle abc has vertices at a(-2 3),B(0,3),c(-1,-1). Find the coordinates of the image after a reflection over the x-axis.

Crazy boy [7]

The new coordinates of the triangle after reflection from x-axis would be A(-2, -3) , B(0, -3) and C( -1, 1 )

<u>Explanation:</u>

The vertices of the triangle are A(-2 3), B(0,3), C(-1,-1)

The reflection is over the x-axis.

When the reflection is along the x-axis, the coordinates of x does not change. However, the coordinates of y does change.

The negative value of y becomes positive and the positive value of y becomes negative.

Similarly,

A(-2, 3) would become A(-2, -3)

B(0, 3) would become B(0, -3)

C(-1, -1) would become C( -1, 1 )

Therefore, the new coordinates of the triangle after reflection from x-axis would be A(-2, -3) , B(0, -3) and C( -1, 1 )

6 0

3 years ago

Tell whether the given number is a solution of each question. ( Must show work for credit)

guajiro [1.7K]

Answer/Step-by-step explanation:

1. $9 = 2a + 3$ ; 3

Let's solve for a.

$9 - 3 = 2a$ (subtraction property of equality)

$6 = 2a$

$\frac{6}{2} = a$ (division property of equality)

$3 = a$

$a = 3$

Therefore, 3 is a solution to 9 = 2a + 3

2. $5n - (-30) = 5$ ; 7

$5n + 30 = 5$ (- × - = +)

$5n = 5 - 30$ (Subtraction property of equality)

$5n = -25$

$\frac{5n}{5} = \frac{-25}{5}$ (division property of equality)

$n = -5$

Therefore, 7 is not a solution of $5n - (-30) = 5$

3. $4.4r - 2.8 = 1.6$ ; 1

$4.4r = 1.6 + 2.8$

$4.4r = 4.4$

$\frac{4.4r}{4.4} = \frac{4.4}{4.4}$

$r = 1$

Therefore, 1 is a solution of $4.4r - 2.8 = 1.6$ .

5 0

2 years ago

julia-pushkina [17]

The answer to this question is C

6 0

3 years ago