Question

What is the equation of the line that passes through the point (6,-4) and has a slope of-1/3

Answer 1

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$\text{\textbf{Hello!} In this question, we are trying to figure out the \underline{equation} of the line}\\\text{with the given information.}$
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$\textbf{Explanation:}\\\quad{}\\\text{In the question, we were given our \emph{slope} and a \emph{point}.}\quad{}\\\\\text{Slope: -1/3 }\\\\\text{Point: (6, -4)}\\\quad{}\\\text{We can use the information above to help solve our question.}\\\text{In order to find the equation, we will be using the \underline{point-slope formula:}}\\\quad{}\\y - y1 = m(x - x1)\\\quad{}\\\text{With this equation, we would plug in our given values and solve.}$
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$\textbf{Solve:}\\\\y - y1 = m(x - x1)\quad{}\\\\\text{Plug in -1/3 to m, 6 to x1, -4 to y1 and then solve.}\\\\y - (-4) = -1/3(x - 6)\\\\y + 4 = -1/3x + 2\\\\\fbox{y = -1/3x - 2}$
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$\textbf{Answer:}\\\\\text{Therefore, the equation of the line would be: \fbox{y = -1/3x - 2}}$
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