A pyramid with a slant height 4.6 in whose triangular base measures 8 in on each side.Each altitude of the base measures of 6.9
1 answer:
Answer:
82.8 in²
Step-by-step explanation:
The surface area a triangular based pyramid :
Base area + 1/2(perimeter * slant height)
Base = 8 inches ; Slant height = 4.6 inches ; altitude of base measure = 6.9 inches
Base area of triangle :
1/2 * base * height
1/2 * 8 * 6.9
4 * 6.9
Base area = 27.6 in²
The perimeter, P = sum of sides ; (s1 + s2 + s3
P = 8 + 8 + 8 = 24 in
Hence,
Surface area = 27.6 in² + 1/2(24*4.6)
Surface area = 27.6 in² + (12 * 4.6) in²
Surface area = (27.6 + 55.2)
Surface area = 82.8 in²
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and the numerator, yields no critical points either, so the only check you can do is for the endpoints, of 0 and 4
f(0) = 0 <---- only maximum, and thus absolute maximum
f(4) ≈ - 0.19 <---- only minimum, and thus absolute minimum