Answer:

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution
and for this case we know that the distribution is given by:

And the standard error would be:

And replacing we got:

Step-by-step explanation:
For this case we know the population deviation given by:

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution
and for this case we know that the distribution is given by:

And the standard error would be:

And replacing we got:

Answer:
![y=\frac{c}{\sqrt[]{x^2+1} }](https://tex.z-dn.net/?f=y%3D%5Cfrac%7Bc%7D%7B%5Csqrt%5B%5D%7Bx%5E2%2B1%7D%20%7D)
Step-by-step explanation:
(1 + x²)dy +xydx= 0

Integrate both side
![lny=-\frac{1}{2} ln(x^2+1)+c\\y=\frac{c}{\sqrt[]{x^2+1} }](https://tex.z-dn.net/?f=lny%3D-%5Cfrac%7B1%7D%7B2%7D%20ln%28x%5E2%2B1%29%2Bc%5C%5Cy%3D%5Cfrac%7Bc%7D%7B%5Csqrt%5B%5D%7Bx%5E2%2B1%7D%20%7D)
Answer:
Step-by-step explanation:
(-3)(2)= -6
(l^2w^3)(lw^4) = l^3w^7
-6l^3w^7