Answer:
The median score of class A is 73
The interquartile range of class B is 8
The difference of the medians of class A and class B is 9
the interquartile range of either data set should be 8 because that is what b was.
Step-by-step explanation:
The interquartile range is the difference between the upper quartile and the lower quartile. In example 1, the IQR = Q3 – Q1 = 87 - 52 = 35. The IQR is a very useful measurement. It is useful because it is less influenced by extreme values as it limits the range to the middle 50% of the values.
£1 = 99.72 rupees -> £450 = 44874 rupees.
As the post office only has 500 rupee papers, once we calculate out the result, we have to round down to the nearest whole number.
The amount of rupee papers we can change out is : 44874 : 500 = 89.748 (papers)
We round down to 89 papers.
It is given that the circumference of the circle is 19.5 inches. Let the diameter is d inches .
And the formula of circumference is

Substituting the value of C, we will get

When the diameter increased by 3, then the circumference is

And the circumference , when diameter is increased by 3 is 29 inches .
The ratio 9/15 and 6/15 form a proportion
STEP 1:
convert meters to centimeters
100 cm= 1 meter
= 100 cm/m * 2.5 m
= 250 cm
STEP 2:
x= length of first shelf
2x+18= length of second shelf
x-12= length of third shelf
x+4= length of fourth shelf
since the whole board has to be used, add lengths of all shelves and set it equal to the whole length of the board (250 cm).
x + (2x+18) + (x-12) + (x+4)= 250 cm
combine like terms
5x + 10= 250
subtract both sides by 10
5x= 240
divide both sides by 5
x= 48
STEP 3:
find length of second shelf
= 2x + 18
= 2(48) + 18
= 114 cm
CHECK:
x + (2x+18) + (x-12) + (x+4)= 250
48 + (2(48)+18) + (48-12) + (48+4)= 250
48 + (96+18) + 36 + 52= 250
48 + 114 + 36 + 52= 250
250= 250
ANSWER: Shelf two is 114 cm.
Hope this helps! :)