Answer:
4*x^4*y^22
Step-by-step explanation:
Your goal here is to REDUCE the given expression to simplest terms.
One way in which to approach this problem would be to rewrite (2x^2y^10)^3 as: (2x^2*y^8)*y^2*(2x^2*y^10)^2.
Dividing this rewritten expression by 2x^2*y^8 results in:
y^2(2x^2*y^10)^2.
We now need to raise (2x^2*y^10) to the power 2. Doing this, we get:
4x^4*y^20.
Multiply this by y^2 (see above):
y^2*4x^4*y^20
The first factor is 4: 4y^2*x^4*y^20. This is followed by the product of y^2 and y^20: 4*y^22*x^4
Finally, this should be re-written as
4*x^4*y^22
Another way of doing this problem would involve expanding the numerator fully and then cancelling out like factors:
8*x^6*y^30 4*x^4*y^22
----------------- = ------------------ = 4*x^4*y^22
2x^2y^8 1
Answer:
C
Step-by-step explanation:
It is not E becuase SQRT(97) is less than SQRT(100), SQRT(100) is 10,
SQRT(81) is 9 SO SQRT(97) is between 9 and 10, C.
Hope it helps :)
Answer: option d. x = 3π/2Solution:function y = sec(x)
1) y = 1 / cos(x)
2) When cos(x) = 0, 1 / cos(x) is not defined
3) cos(x) = 0 when x = π/2, 3π/2, 5π/2, 7π/2, ...
4) limit of sec(x) = lim of 1 / cos(x).
When x approaches π/2, 3π/2, 5π/2, 7π/2, ... the limit →+/- ∞.
So, x = π/2, x = 3π/2, x = 5π/2, ... are vertical asymptotes of sec(x).
Answer: 3π/2
The figures attached will help you to understand the graph and the existence of multiple asymptotes for y = sec(x).
Answer: Here.
The Solid formed by the net will be a rectangular pyramid.
There are TWO sets of opposite congruent triangular faces.
The base has an area of 30m2
Step-by-step explanation: Don't listen to the B and C dude.
Answer:
the answer would be three because when an exponent is on the inside of the parenthesis and one is outside too, then they are multiplied. If it wasn't, then it would be added.
Step-by-step explanation: