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USPshnik [31]
3 years ago
9

Help please pre calculus

Mathematics
1 answer:
Jobisdone [24]3 years ago
6 0
Since a log graph is with base 10 and a ln graph is with base e (2.something), the log x graph will clearly have smaller numbers (as, for example, log100=2 and ln100=around 4.6). In addition, you only have to multiply a number by e to increase the power by 1 but you have to multiply a number by 10 (which is significantly larger than e) to increase logx's power by 1, therefore proving that the log x graph will grow slower
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The cost of Spectrum Internet is $60 per month plus a one time $35 installation fee. How much would it cost to have internet for
Murljashka [212]

Answer:

$755

Step-by-step explanation:

You can use the formula c = 60m + 35 for this. c is the cost and m is the number of months. Since a year is 12 months, 60m = 60*12 = 720. Then add the one time fee of $35. 720 + 35 = 755.

4 0
3 years ago
Jillian is trying to save water, so she reduces the size of her square grass lawn by 8 feet on each side. the area of the smalle
tatiyna
(x - 8)^2 = 144
take the sq rt of both sides
x - 8 = 12
x = 12 + 8
x = 20

20 feet by 20 feet
7 0
3 years ago
Read 2 more answers
How do you construct congruent segments, segment bisectors, angles, and angle bisectors using tools such as a compass and straig
poizon [28]
You use a compass to draw angles and straightedge to draw the shapes.



4 0
3 years ago
Solve for x.4(2x + 3) = 3x + 3 + 2x
ElenaW [278]

Answer:

The value of x is -3.

Explanation:

Given the equation:

4\mleft(2x+3\mright)=3x+3+2x​

Step 1: Distribute 4 in the left-hand side.

\begin{gathered} 4\mleft(2x)+4(3\mright)=3x+3+2x​ \\ 8x+12=3x+2x​+3 \\ 8x+12=5x​+3 \end{gathered}

Step 2: Collect like terms.

\begin{gathered} 8x-5x=3-12 \\ 3x=-9 \end{gathered}

Step 3: Divide both sides by 3.

\begin{gathered} \frac{3x}{3}=-\frac{9}{3} \\ x=-3 \end{gathered}

The value of x is -3.

3 0
1 year ago
ppl plz answer my question with the three picks of table of values i really need it to boost my grade up plzzzzzz
hjlf
Wheres the question lol..
7 0
3 years ago
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