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USPshnik [31]
3 years ago
9

Help please pre calculus

Mathematics
1 answer:
Jobisdone [24]3 years ago
6 0
Since a log graph is with base 10 and a ln graph is with base e (2.something), the log x graph will clearly have smaller numbers (as, for example, log100=2 and ln100=around 4.6). In addition, you only have to multiply a number by e to increase the power by 1 but you have to multiply a number by 10 (which is significantly larger than e) to increase logx's power by 1, therefore proving that the log x graph will grow slower
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Multiply two and four-fifths negative five and two-thirds<br><br> whats the answer
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The answer to your question is -16/3
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3 years ago
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The tree diagram below shows all of the possible outcomes for flipping three coins.
creativ13 [48]

The probability that two of the coins will be tails is 1/2

It is 1/2 because "at least two tails" means that two tails and the rest of the number of tails, which is 3. In total the three coins have 6 sides. The chance of having two tails and one is three out of 6, simplified is 1/2 ;)

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What is the property that is shown?
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3 0
3 years ago
Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Then find the area of the re
mina [271]

Answer:

Step-by-step explanation:

integrate with respect to x

Area is symmetric so will be twice the integral from zero to 1

( I cannot seem to figure out how to make the lower limit negative in this editor)

A = 2\int\limits^1_0 {(x^2 + 3) - 4x^2} \, dx)

A = 2\int\limits^1_0 {-3x^2 + 3} \, dx

A = 6\int\limits^1_0 {-x^2 + 1} \, dx

A = 6(-⅓x³ + x)\left \| {{x=1} \atop {x=0}} \right.

A = 6((-⅓(1)³ + (1)) - (-⅓(0)³ + (0)))

A = 6(⅔)

A = 4 units²

7 0
2 years ago
An integer is 15 more than 2 tomes another. If the product of two integers is -27 then find the integers
andre [41]

Answer:

x = 9 and y = -3

Step-by-step explanation:

Let's say the first integer is x and the second one is y. Then, if we put the words into mathematical expressions, we get:

x = 15 + 2y

xy = -27

We can use substitution to solve this system of equations. We put 15 + 2y in for x in xy = -27:

(15 + 2y)*y = -27 ⇒ 2y² + 15y = -27 ⇒ 2y² + 15y + 27 = 0

Now, we have a quadratic to solve, so after some trial and error, we get:

(2y + 9)*(y + 3) = 0

Setting each of these to 0, we get two possible answers for y:

y = -9/2 or y = -3.

However, it says that y is an integer, so it can't be -9/2 and must be -3. We use this to find x:

x = 15 + 2*(-3) = 15 - 6 = 9

So, the two numbers are x = 9 and y = -3.

7 0
3 years ago
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