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Volgvan
3 years ago
13

What is the first quartile of the data displayed in this box-and-whisker plot?

Mathematics
2 answers:
Lana71 [14]3 years ago
5 0
The answer is C. 37. To get this, look at the line that makes up to left side of the box.
Mekhanik [1.2K]3 years ago
4 0

Answer:

C

Step-by-step explanation:

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Write an absolute value function that shifted 2<br> units right.<br><br> HELPPPP
iVinArrow [24]

Answer: (a)

Step-by-step explanation:

Suppose the original function is y=\left | x \right |

To shift it 2 units right, replace x by x-2 such that

\Rightarrow x-2=0\\\Rightarrow x=2

So, the function becomes y=\left | x -2\right |

4 0
2 years ago
Mr. Gordon weighs 205 pounds . Multiply his earth weight by 0.91 to find out how much he would weigh on the planet Venus. What i
Savatey [412]
When you multiply 205 by 0.91 you get 186.55 and 205 minus 186.55 is 18.45
5 0
3 years ago
AB = 5x -9; BC= -2x + 12
BaLLatris [955]

Answer:

X=-3

Step-by-step explanation:

5x - 9

-2x + 12

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7x = -21

X= -3

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3 0
2 years ago
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nalin [4]
25 candy in a bag, if 2/5 or 40% of candy is caramels. Then 10 in each bag is caramels.

Your answer would be C.
3 0
2 years ago
Read 2 more answers
Find an equation of the sphere with center (2, −10, 3) and radius 5. $$25=(x−2)2+(y−(−10))2+(z−3)2 use an equation to describe i
lana66690 [7]

In the x,y plane, we have z=0 everywhere. So in the equation of the sphere, we have

25=(x-2)^2+(y+10)^2+(-3)^2\implies(x-2)^2+(y+10)^2=16=4^2

which is a circle centered at (2, -10, 0) of radius 4.

In the x,z plane, we have y=0, which gives

25=(x-2)^2+10^2+(z-3)^2\implies(x-2)^2+(z-3)^2=-75

But any squared real quantity is positive, so there is no intersection between the sphere and this plane.

In the y,z plane, x=0, so

25=(-2)^2+(y+10)^2+(z-3)^2\implies(y+10)^2+(z-3)^2=21=(\sqrt{21})^2

which is a circle centered at (0, -10, 3) of radius \sqrt{21}.

3 0
3 years ago
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