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JulijaS [17]
3 years ago
14

What is the component form of the vector whose tail is the point (-3,2) and whose head is the point (1, -6)?

Mathematics
1 answer:
Bess [88]3 years ago
4 0

Answer:

  (4, -8)

Step-by-step explanation:

The components of a vector are found by subtracting the tail from the head.

__

  Head - Tail = (1, -6) -(-3, 2) = (1 -(-3), -6 -2) = (4, -8)

⇒ The component form is (4, -8), or maybe 4<em>i</em> -8<em>j</em>.

_____

<em>Additional comment</em>

There are many ways that the components of vectors can be described. The particular format you are expected to use will likely be found in your curriculum materials.

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X/25 - 4/5 = -3/5<br><br><br> The solution for x =
melisa1 [442]

Answer:

X=5

Step-by-step explanation:

plz mark as brainliest

8 0
4 years ago
If 8 identical blackboards are to be divided among 4 schools,how many divisions are possible? How many, if each school mustrecei
MAXImum [283]

Answer:

There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.

Step-by-step explanation:

Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.

 The problem reduces to take 11 consecutive spots which we will use to localize the balls and the sticks and select 3 places to put the sticks. The amount of ways to do this is {11 \choose 3} = 165 . As a result, we have 165 ways to distribute the blackboards.

If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is {7 \choose 3} = 35. Thus, there are only 35 ways to distribute the blackboards in this case.

4 0
4 years ago
Why is the median better to represent the data of a stem and leaf plot? I NEED THE ANSWER NOW PLSSSS
jeyben [28]

Answer:

The median value is better because it is not affected by the skewness of the data

Step-by-step explanation:

The median is  better in representing the data of a stem and leaf plot because the median value is not affected so much by outliers and skewness of the data. for example:  for a downward skewed stem and leaf plot the value of the median is greater than the mean value

Hence the median value is a better representation of the central tendency

6 0
3 years ago
Lanya's house is located at (2 2/3, 7 1/3) on a map. The store where she works is located at (-1 1/3, 7 1/3). what is the distan
notka56 [123]

Answer:

Option A: 4 units is the correct answer.

Step-by-step explanation:

Given that:

Layana's house is located at (2\frac{2}{3}, 7\frac{1}{3})

Store is located at (-1\frac{1}{3},7\frac{1}3})

We can find distance between two points by using distance formula.

S = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2

The points can also be written as;

House (8/3, 22/3)

Store (-4/3, 22/3)

Putting values in the formula.

S = \sqrt{\frac{8}{3}-(-\frac{4}{3}))^2+(\frac{22}{3}-\frac{22}{3})^2

S = \sqrt(\frac{8}{3}+\frac{4}{3}+0

S = \sqrt{(\frac{8+4}{3})^2

S = \sqrt{(\frac{12}{4})^2

S = \sqrt{(4)^2

S = 4 units

Hence,

Option A: 4 units is the correct answer.

7 0
3 years ago
Select the correct answer from each drop-down menu.
Basile [38]

The first one is "unit of account".

The second one is "store of value".

The third one is "medium of exchange".

3 0
4 years ago
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