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3 years ago

Someone please help me ASAP

Mathematics

1 answer:

Ivanshal [37]3 years ago

7 0

Step-by-step explanation:

a vector multiplied by a scalar is equal to it's image. The expression above gives an equation and after solving, it gives you the image

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Match each pair of points to the equation of the line that is parallel to the line passing through the points.

Luba_88 [7]

Answer:

$B(5,2) \:\: C(7,-5) \:\: \rightarrow y=-3.5x-15$

$D(11,6)\:\: E(5,9)\:\: \rightarrow y=-0.5x-3$

$H(4,4)\:\: I(8,9) \:\: \rightarrow y=1.25x+4$

$L(5,-7)\:\: M(4,-12)\:\: \rightarrow y=5x+9$

Step-by-step explanation:

We need to match the slope of the function with the slope of the lines connecting the two points given. The slope of the lines are as follows:

$B(5,2) \:\: C(7,-5)=\frac{2--5}{5-7} =-3.5$

$D(11,6)\:\: E(5,9)=\frac{6-9}{11-5} =-0.5$

$H(4,4)\:\: I(8,9)=\frac{4-9}{4-8} =1.25$

$L(5,-7)\:\: M(4,-12)=\frac{-7--12}{5-4} =5$

$F(-7,12)\:\: G(3,-8)=\frac{12--8}{-7-3}=-2$

$J(7,2)\:\:K(-9,8) =\frac{2-8}{7--9} =-0.375$

Now,

the slope of the line BC matches with the slope of y=-3.5x-15.

the slope of the line DE matches with the slope of y=-0.5x-3.

the slope of the line HI matches with the slope of y=1.25x+4.

the slope of the line LM matches with the slope of y=5x+9.

and the slopes of the lines FG and JK do not match with any of the functions given.

Thus,

$B(5,2) \:\: C(7,-5) \:\: \rightarrow y=-3.5x-15$

$D(11,6)\:\: E(5,9)\:\: \rightarrow y=-0.5x-3$

$H(4,4)\:\: I(8,9) \:\: \rightarrow y=1.25x+4$

$L(5,-7)\:\: M(4,-12)\:\: \rightarrow y=5x+9$

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