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malfutka [58]
2 years ago
6

What is the volume of a cylinder, in cubic feet, with a height of 13 feet and a base

Mathematics
1 answer:
VashaNatasha [74]2 years ago
6 0

Answer:

163.3

Step-by-step explanation:

3.14*r^2*h

h=13

4/2 = 2

r=2

2^2 = 4

3.14*4 = 12.56

12.56*13 = 163.28

Rounded = 163.3

I believe the answer is 163.3

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Event A has probability 0.4. Event B has probability 0.5. If A and B are disjoint, what is the probability that both events occu
Mnenie [13.5K]

Answer:

0

Step-by-step explanation:

Given that:

The probability of event A = 0.4

i.e. P(A) = 0.4

The probability of  event B = 0.5

P(B) = 0.5

Given that A and B are disjoint, then they do not have any elements in common. Thus, the probability that both events will occur is;

P(A ∩ B) = empty set {}, and the cardinality of the intersection of these two disjoint sets are, therefore, zero (0).

8 0
3 years ago
1. Use the cosine and sine functions to express the exact coordinates of P in terms of angle θ.
Luden [163]

Answer:

For a point defined bt a radius R, and an angle θ measured from the positive x-axis (like the one in the image)

The transformation to rectangular coordinates is written as:

x = R*cos(θ)

y = R*sin(θ)

Here we are in the unit circle, so we have a radius equal to 1, so R = 1.

Then the exact coordinates of the point are:

(cos(θ), sin(θ))

2) We want to mark a point Q in the unit circle sch that the tangent has a value of 0.

Remember that:

tan(x) = sin(x)/cos(x)

So if sin(x) = 0, then:

tan(x) = sin(x)/cos(x) = 0/cos(x) = 0

So tan(x) is 0 in the points such that the sine function is zero.

These values are:

sin(0°) = 0

sin(180°) = 0

Then the two possible points where the tangent is zero are the ones drawn in the image below.

7 0
3 years ago
What is a1 of the arithmetic sequence for which a3=126 and a64=3,725
Evgesh-ka [11]
D=an-am/n-m
d=a64-a3/64-3
d=3725-126/61=59
a3=a1+2d
126=a1+118
a1=8
7 0
4 years ago
Read 2 more answers
4. A rocking horse has a weight limit of 60 pounds.
forsale [732]
A. 33/60=55%
b. 114/60=190%
c. .95•60=57
3 0
3 years ago
Read 2 more answers
U 1995, 70% of all children in the U.S. were living with both parents. If 25 children were selected at random in the U.S., what
nikdorinn [45]

<u>Answer:</u>

The probability that at most 10 of them will be living with both of their parents is 0.0018

<u>Solution:</u>

Given, US 1995, 70% of all children in the U.S. were living with both parents.  25 children were selected at random in the U.S.,  

We have to find what is the probability that at most 10 of them will be living with both of their parents?  

Now, number of children picked (n) = 25.

Probability to be with parents = 70% = 0.7.

Our condition is 0 ≤ x ≤ 10.

Then, we have to calculate p(0 ≤ x ≤ 10).

We can calculate using binomial cumulative distribution frequency- binomial CDF

Now, p(0 ≤ x ≤ 10) = binomcdf(n, p, x) = binomcdf(25, 0.7, 10) = 0.00177840 ≈ 0.0018.

Hence, the probability is 0.0018

6 0
3 years ago
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