If 3mile=28 min
x mile=42 min
cross multiply
x=3/28
therefore if 3/28=1 min
then x mile= 42 min
cross multiply
42 x 3/28 =21 x 3/14
=3 x 3/1
=9
The answer is 9 miles
Answer: The flagpole is about 22.3 feet tall.
This is roughly the size of a two story building, assuming each floor is 10 feet or so.
Since this height is under 25 ft, this flagpole is in compliance with the regulation.
=====================================================
Work Shown:
The horizontal leg of the triangle is 36 ft. This is the adjacent leg to the reference angle 25 degrees.
The vertical leg of the triangle is x-5.5, and this leg is the opposite side to the reference angle 25 degrees.
Use the tangent rule to connect the opposite and adjacent sides.
Solve for x.
tan(angle) = opposite/adjacent
tan(25) = (x-5.5)/36
36*tan(25) = x-5.5
x-5.5 = 36*tan(25)
x = 36*tan(25)+5.5
x = 22.28707569358
x = 22.3 ft is the approximate height of the flagpole
Make sure your calculator is in degree mode.
The height is not over 25 ft, so this flagpole meets the requirements.
Answer: 3 - 2x
I’m not sure if you meant xxx or not.
So 36.67\12= 3.055833 and the 3 repeats so round up the 5 to get 3.06
Hope I’m correct!
It was rounded to the nearest Ten thousands.(710,430)
Hope i helped!!!!:D
