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Svetradugi [14.3K]
3 years ago
7

Find the area of the shaded region. Round your answer to the nearest tenth. PLZ HELP

Mathematics
2 answers:
Ksju [112]3 years ago
6 0

Answer:

30.96 m²

Step-by-step explanation:

In white there are four parts of a circle, so we can split the 12 m in half to show the radius, and then solve to find the area of the full circle.

A = r²

a = (6)²

a = (36)

a = 113.04

Then you find the area of the whole box.

12 x 12 = 144

Then you subtract the area of the circle in white from the area of the whole box.

144 - 113.04 = 30.96 m²

So that’s the area of the shaded region.

Kay [80]3 years ago
6 0

Answer:

283

Step-by-step explanation:

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3 years ago
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What is the numerical solution to the equation five less than three times a number equals four more than eight times rhetorical
Romashka-Z-Leto [24]

Answer:

3n-5=8n+4

Step-by-step explanation:

3 0
3 years ago
The perimeter of a rectangle is 30.8 km and it’s diagonal length is 11 km. Find it’s length and width
blsea [12.9K]

Answer:

Length of the rectangle is 15.0325 km and width is 0.3765 km.

Explanation:

Given:

Perimeter of a rectangle = 30.8 km

Length of diagonal of rectangle = 11 km

To find:

The length and width of rectangle=?

Solution:

Lets assume length of the rectangle = x km

And assume width of the rectangle = y km

Lets first create equation using given  perimeter

perimeter of rectangle = 2 ( length +  width )

=> 30.8 km = 2 ( x + y )  

=>x + y = \frac{30.8}{2}

=> y = 15.4 – x             ------(1)

As diagonal and two sides of rectangle forms right angle triangle whose hypoteneus is diagonal ,  

=> length^2 + width^2 = diagonal^2

=> x^2 + y^2 = 11^2

=> x^2 + y^2 = 121

On substituting value of y from (1) in above equation we get

=> x^2 + (15.4-x)^2 = 121

=>x^2 + (15.4)^2 + x^2 – 2 x 15.4 \times x   = 121

=> 2x^2-30.8x + 237.16 -121  = 0

=> 2x^2-30.8x + 116.16 = 0

Solving above quadratic equation using quadratic formula

General form of quadratic equation is  

ax^2 +bx +c = 0

And quadratic formula for getting roots of quadratic equation is  

x= \frac{ -b\pm\sqrt{(b^2-4ac)}}{2a}

As equation is 2x^2-30.8x + 116.16 = 0, in our case

a = 2 ,  b = -30.8 and c = 116.16

Calculating roots of the equation we get

x=\frac{ -(-30.8)\pm\sqrt{(-30.8)^2-4(2)( 11)} } {(2\times2)}

x=\frac{30.8\pm\sqrt{(948.64-88)}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{(30.8\pm29.33)}4

x=\frac{(30.8+29.33)}{4}

x=\frac{(30.8-29.33)}{4}

=> x = 15.0325 or x = 0.3675

As generally length is longer one ,  

So x = 1.0325

From equation (1) y = 15.4 – x = 0.3765

Hence length of the rectangle is 15.0325 km and width is 0.3765 km.

6 0
3 years ago
What is the value of x?
Makovka662 [10]

Answer:

A-100

Step-by-step explanation:

Use the Pythagorean therom.

a^2+b^2=c^2

6^2+8^2=c^2

36+64=100.

Hope this helps. Kinda confused me.


4 0
3 years ago
The segments shown below could form a triangle ac=9. cb=8. ba=17
krek1111 [17]
The lengths of sides of a triangle have to satisfy the triangle inequality, which states that the sum of the two shorter sides must exceed the length of the third side.

Here 9+8=17 (not greater), so these segments do not form a triangle.
8 0
2 years ago
Read 2 more answers
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