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andrezito [222]
3 years ago
7

Sketch the curve represented by the parametric equations. Use arrows to indicate the direction of the curve as t increases. Find

a rectangular-coordinate equation for the curve by eliminating the parameter. Express the vector v with initial point P and terminal point Q in component form. (Assume that each point lies on the gridlines.)

Mathematics
1 answer:
Paul [167]3 years ago
8 0

The <em>lower right</em> image represents the image of the <em>parametric</em> formulas, whose <em>rectangular</em> formula is \frac{x^{2}}{16} + \frac{y^{2}}{25} = 1. The vector in <em>component</em> form is \vec v = (8, -4).

<h3>How to analyze parametric equations and vectors</h3>

<em>Parametric</em> formulas are <em>vectorial</em> expressions in terms of a parameter (t). Planar parametric expression are of the form \vec r(t) = (x(t), y(t)). Ellipses centered at the origin are described by the following expression:

\vec r (t) = (a\cdot \cos t, b \cdot \sin t)     (1)

Where a, b are the lengths of the <em>major</em> and <em>minor</em> semiaxes.

By direct observation of the given <em>parametric</em> equations, we conclude that the ellipse of the lower <em>right</em> image represents the two equations.

The <em>rectangular</em> equation of the ellipse is found by eliminating the parameter:

\cos ^{2}t + \sin ^{2}t = 1  

(\frac{x}{4})^{2} + \left(\frac{y}{5} \right)^{2} = 1

\frac{x^{2}}{16} + \frac{y^{2}}{25} = 1

According to the geometry, vectors can be generated from two points, one of them as the <em>initial</em> point. A vector can be defined as a subtraction between two vectors with <em>initial</em> points at the origin:

\vec v = B(x, y) - A(x, y)     (2)

Where:

  • A(x, y) - Initial point
  • B(x, y) - Final point

If we know that A(x, y) = (1, 8) and B(x, y) = (9, 4), then the equation of the vector is:

\vec v = (9, 4) - (1, 8)

\vec v = (9 - 1, 4 - 8)

\vec v = (8, -4)

To learn more on parametric equations: brainly.com/question/12718642

#SPJ1

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Answer:

\displaystyle  a_{1}    = 108

Step-by-step explanation:

we are given

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\displaystyle S_{ \text{n}} =  \frac{ a_{1}(1 -  {r}^{n} )}{1 - r}

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\displaystyle  \frac{ a_{1}(1 -  {( \frac{1}{2} )}^{3} )}{ \dfrac{1}{2}  }  = 189

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simplify complex fraction:

\displaystyle   a_{1} (\frac{7}{8} ) \div { \frac{1}{2}  }  = 189

calculate reciprocal:

\displaystyle   a_{1} \frac{7}{8}   \times 2  = 189

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\displaystyle   a_{1} \frac{7}{4}   \  = 189

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\displaystyle   a_{1} \frac{7}{4}  \times  \frac{4}{7}   \  = 189 \times  \frac{4}{7}

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\displaystyle   a_{1}     = 27\times  4

simplify multiplication:

\displaystyle  a_{1}    = 108

hence,

\displaystyle  a_{1}    = 108

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