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1 year ago

The slope of the line below is -1/7.

Mathematics

1 answer:

KatRina [158]1 year ago

3 0

Answer:

y = (-1/7)x + (24/7)

Step-by-step explanation:

The general structure of a line in slope-intercept form is:

y = mx + b

In this form, "m" represents the slope and "b" represents the y-intercept.

You have been given the value of the slope (m = -1/7). You have also been given values for "x" and "y" from the point (3,3). Therefore, you can substitute these values in for their variables and simplify to find the value of the y-intercept.

y = mx + b <----- Slope-intercept form

y = (-1/7)x + b <----- Plug -1/7 into "m"

3 = (-1/7)(3) + b <----- Plug in "x" and "y" values from point (3,3)

3 = -3/7 + b <----- Multiply -1/7 and 3

24/7 = b <----- Add 3/7 to both sides

Now that you know that m = -1/7 and b = 24/7, you can determine the formula satisfying the given information.

y = (-1/7)x + (24/7)

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3 years ago

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3 years ago

(Urgent!!) Find the value of x

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Step-by-step explanation:

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2 years ago

Test the claim that the mean GPA of night students is larger than 3.1 at the .10 significance level. The null and alternative hy

Alborosie

Answer:

H 0 : μ = 3.1 H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

$t = \frac{3.13-3.1}{\frac{0.03}{\sqrt{75}}}= 8.66$

$df = n-1=75-1 =74$

The p value is:

$p_v = P(t_{74} >8.66) =3.65x10^{-13}$

The significance level is: 0.1 or 10%

And since the p value is very low compared to the significance level we have enough evidence to:

Reject the null hypothesis

Step-by-step explanation:

For this case we want to test the claim that mean GPA of night students is larger than 3.1 at the .10 significance level. The claim needs to be on the alternative hypothesis so then we have the following system of hypothesis:

H 0 : μ = 3.1 H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

We have the following info given:

$\bar X = 3.13 , s =0.03 , n =75$

The statistic to check the hypothesis is given by:

$t = \frac{\bar X -\mu}{\frac{s}{\sqrt{n}}}$

Replacing the info given we got:

$t = \frac{3.13-3.1}{\frac{0.03}{\sqrt{75}}}= 8.66$

The degrees of freedom are given by:

$df = n-1=75-1 =74$

The p value since is a right tailed ted is given by:

$p_v = P(t_{74} >8.66) =3.65x10^{-13}$

The significance level is 0.1 or 10%

And since the p value is very low compared to the significance level we have enough evidence to:

Reject the null hypothesis

6 0

3 years ago

Solve the inequalities -150x ≥ − 2,400 and -336 ≥ − 21y.

astra-53 [7]

Ok so easy peasy
remember that when divide or multiply by negative, reverse the inequality symbol example
2>3 times -1=
-2<-3 so

-150x>-2400
divide both sides by -150
flip sign
x<16

-336>-21y
divide both sides by -21
flip sign
16<y

they seem to have the same solution

x=y>16

4 0

3 years ago

Read 2 more answers