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Nitella [24]
3 years ago
14

The health care Jimmy’s employer offers is a fee-for-service plan in which Jimmy and his family must pay for $12,500 in health r

elated services in a calendar year before the insurance company begins to pay.  Jimmy and his family have several health related issues that demand $685.00 each month.  If one of Jimmy’s children were to become seriously injured at the end of the year, how much more would Jimmy and his family need to pay before the insurance company begins  to assume responsibility?
a.
$984.58
b.
$4,280.00
c.
$11,815.00
d.
$14,417.92
Mathematics
1 answer:
Ostrovityanka [42]3 years ago
3 0
The answer is Letter B - $4,280.00.

Total the amount they could incur because of health issues in a year then deduct it from 12,500.

   = 685 x 12 months
   = 8,220; they incur $8,220 for their health related issues in a year

   = 12,500 - 8,220
   = 4,280; amount they need to pay before the insurance company assumes responsibility.
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Which expressions are equivalent to g+h+ (j+k)? Check all that apply.
Vsevolod [243]
According to the associative property of equality: (a + b) + c = a + (b + c) we can see that the parenthesis do not mean anything when we are only doing addition.

So answers 1. and 3. are correct.

<em>Thanks Associative Property!</em>
6 0
3 years ago
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Consider the following information related to a set of quantitative sample data:
svlad2 [7]

Answer:

(a) There are outliers

(b) x and x >62

Step-by-step explanation:

Given

\sigma = 14.92

\bar x = 22.0

q_0 = -24

q_1 = 14.5

q_2 = 24.5

q_3 = 33.5

q_4 = 64

Solving (a): Check for outliers

This is calculated using:

Lower = Q_1 - (1.5 * IQR) --- lower bound of outlier

Upper = Q_3 +(1.5 * IQR) --- upper bound of outlier

Where

IQR = Q_3 - Q_1

So, we have:

IQR = 33.5 - 14.5

IQR = 19

The lower bound of outlier becomes

Lower = Q_1 - (1.5 * IQR)

Lower = 14.5 - (1.5 * 19)

Lower = 14.5 - 28.5

Lower = -14

The upper bound of outlier becomes

Upper = Q_3 +(1.5 * IQR)

Upper = 33.5 + 1.5 * 19

Upper = 33.5 + 28.5

Upper = 62

So, we have:

-14 \le x \le 62 --- the range without outlier

Given that:

q_0 = -24  --- This represents the lowest data

q_4 = 64   --- This represents the highest data

-24 and 64 are out of range of -14 \le x \le 62.

Hence, there are outliers

Solving (b): The outliers

The outliers are data less than the lower bound (i.e. less than -14) or greater than the upper bound (i.e. 62)

So, the outliers are:

x and x >62

4 0
2 years ago
Multiple Choice
Zanzabum

A) Answer: A. 22.5 cm, 30 cm, and 37.5 cm


Setting the unity measurement as x, the three sides will be 3·x, 4·x, and 5·x. The sum of the three sides will be (3 + 4 + 5)·x = 12·x; this corresponds to the perimeter, therefore:

12·x = 90 cm


We can solve for x:

x = 90 / 12 = 7.5 cm


Hence, the sides will be:

7.5 · 3 = 22.5 cm

7.5 · 4 = 30 cm

7.5 · 5 = 37.5 cm


This situation is represented in option A (which is also the only option whose sides add up to 90).



B) Answer: C. never true


We have:

6 + 8x - 9 = 11x + 14 - 3x


Bring all the terms with x on the left, by subtracting from both sides 11x and -3x, and all the numbers on the right by subtrcting from both sides 6 and -9:

6 + 8x - 9 - 11x - (-3x) - 6 - (-9) = 11x + 14 - 3x - 11x - (-3x) - 6 - (-9)


Cancel out the opposite terms from each side:

8x - 11x + 3x = 14 - 6 + 9


Combine likely terms:

0x = 17


Now you should ask yourself: what number multiplied by zero gives 17 as a result? The answer is none because a number multiplied by zero always equals zero.


Hence, the statement is never true.


C) Answer: r \leq \frac{1}{5}


We have:

5r + 4 ≤ 5


Subtract 4 from both sides:

5r + 4 - 4 ≤ 5 - 4


Combine likely terms:

5r ≤ 1


Divide both sides by 5:

\frac{5r}{5} \leq \frac{1}{5}

r \leq \frac{1}{5}


To graph the set of solutions, you need to set:

y₁ = 5x + 4 and

y₂ = +5


Plot these two lines:

y₂ is a horizontal line at a height of 5;

y₁ is a line passing through (0, 4) and (1, 9)


The set of solutions will be the part of the graph in which y₁ lies underneath y₂ (see picture attached), that happens for x \leq \frac{1}{5}.





4 0
3 years ago
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Solve the system of equations by substitution. 3/8x + 1/3y = 17/24
VashaNatasha [74]

Answer:

this question is not complete. need another equation

Step-by-step explanation:

give another equation then I can solve

\frac{3}{8} x =  \frac{17}{24}  -  \frac{1}{3} y \\ x =  \frac{17}{9}  -  \frac{8}{9} y

7 0
3 years ago
Three students are from a plate of cookies.Daniel ate 1/12 of the cookies, Mariel ate 4/12 of the cookies, and Tamika ate 2/12 o
Mrac [35]

Answer:

5/12  of cookies left on the plate

Step-by-step explanation:

we have to add to know what part of the dish ate and then subtract it from the total

1/12 + 4/12 + 2/12 =

when we are adding fractions with the same denominator we simply add the above

1 + 4 + 2 = 7

1/12 + 4/12 + 2/12 = 7/12

now to the total of the plate that would be 1 we subtract what they ate

1 - 7/12 =

the whole 1 can be expressed as 12/12 since if we do the 12/12 = 1 account

12/12 - 7/12

for the subtraction with the same denominator the same thing happens as for the sum, we only do it with the top

12 - 7 = 5

12/12 - 7/12 = 5/12

8 0
3 years ago
Read 2 more answers
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