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kumpel [21]
2 years ago
10

X^2 - 3x - 28 factor compleatly

Mathematics
2 answers:
wariber [46]2 years ago
8 0

Answer:

(x - 7)(x + 4)

Step-by-step explanation:

To find the factors, you just need to ask yourself the question: Which two numbers multiply to -28 but add to -3?

Simple guess-and-check will lead you to the numbers -7 and 4.

-7 x 4 = -28

-7 + 4 = -3

These numbers will make up the factored equation.

x² - 3x - 28

(x - 7)(x + 4)

You can check your answer by re-expanding the factored expression. This is done by multiplying each term in the first parentheses by each term in the second parentheses.

(x - 7)(x + 4)  ---->  x² - 7x + 4x - 28  ---->  x² - 3x - 28

slamgirl [31]2 years ago
7 0

Answer:

Step-by-step explanation:

x² - 3x - 28

What factors multiply to -28 and add to -3?

-7 and 4.

(x - 7) (x + 4)

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For the given set, first calculate the number of subsets for the set, then calculate the
vodomira [7]

Answer:

\fbox{\begin{minipage}{14em}Number of subsets: 16\\Number of proper subsets: 15\end{minipage}}

Step-by-step explanation:

<em>Given:</em>

The set A = {5, 13, 17, 20}

<em>Question: </em>

Find the number of subsets of A

Find the number of proper subsets of A

<em>Simple solution by counting:</em>

Subset of A that has 0 element:

{∅} - 1 set

Subset of A that has 1 element:

{5}, {13}, {17}, {20} - 4 sets

Subset of A that has 2 elements:

{5, 13}, {5, 17}, {5, 20}, {13, 17}, {13, 20}, {17, 20} - 6 sets

Subset of A that has 3 elements:

{5, 13, 17}, {5, 13, 20}, {5, 17, 20}, {13, 17, 20} - 4 sets

Subset of A that has 4 elements:

{5, 13, 17, 20} - 1 set

In total, the number of subsets of A: N = 1 + 4 + 6 + 4 + 1 = 16

The number of proper subsets (all of subsets, except subset which is equal to original set A): N = 16 - 1 = 15

<u><em>Key-point:</em></u>

The counting method might be used for finding the number of subsets when the original set contains few elements.

The question is that, for a set that contains many elements, how to find out the number of subsets?

The answer is that: there is a fix formula to calculate the total number (N) of subsets of a set containing n elements: N = 2^{n}

With original set A = {5, 13, 17, 20}, there are 4 elements belonged to A.

=> Number of subsets of A: N = 2^{4} = 16

(same result as using counting method)

<em>Brief proof of formula: N = </em>2^{n}<em />

Each element of original set is considered in 2 status: existed or not.

If existed => fill that element in.

If not => leave empty.

For i.e.: empty subset means  that all elements are selected as not existed, subset with 1 element means that all elements are selected as not existed, except 1 element, ... and so on.

=> From the point of view of a permutation problem, for each element in original set, there are 2 ways to select: existed or not. There are n elements in total. => There are 2^n} ways to select, or in other words, there are 2^{n} subsets.

Hope this helps!

:)

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blagie [28]

Answer:

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Step-by-step explanation:

f(b)-f(a)     12-2              10

---------- = ------------  = -------- = -2

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Please help !<br> (cos Θ − cos Θ)^2 + (cos Θ + cos Θ)^2
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The answer is:  " <span>4 cos² Θ " .
_____________________________________________
Explanation:
_____________________________________________</span>
(cos Θ − cos Θ)²  + (cos Θ + cos Θ)²  

   =   0² + (cos Θ + cos Θ)²  ;

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_____________________________
3 0
4 years ago
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monitta
10 bronze medals

explaining:
if 3 of the medals were gold there would be 15 left. Since there was twice as many bronze from silver they would have 5 silver medals and 10 bronze.
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timofeeve [1]
X=10 ^ 0.59=3.890=3.9
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