9514 1404 393
Answer:
9. rhombus
10. rhombus, rectangle, square
11. rhombus
Step-by-step explanation:
9, 11. Angles are obviously not 90°, so each figure is a rhombus.
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10. Line slopes are 1 or -1, so are perpendicular. Side lengths are all the diagonal of 6 squares, so 6√2.
The figure is a rhombus, rectangle, and square.
Answer:
See Below.
Step-by-step explanation:
We want to use the Squeeze Theorem to show that:
Recall that according to the Squeeze Theorem, if:
And:
Then:
Recall that the value of sine is always ≥ -1 and ≤ 1. Hence:
We can multiply both sides by <em>x</em>². Since this value is always positive, we do not need to change the signs. Hence:
Let <em>g</em> = -<em>x</em>², <em>h</em> = <em>x</em>², and <em>f</em> = <em>x</em>²sin(2 / x). We can see that:
And since g(x) ≤ f(x) ≤ h(x), we can conclude using the Squeeze Theorem that:
The answer to your question is 0.1
Options are not shown but…
A square has 4 equal length sides and a right angle
Or two equal length diagonals which are perpendicular
Or 4 right angled corners and two adjacent sides equal
Or perpendicular diagonals with the same midpoint
Using the last one…
Gradient of AC = (5 - 3)/(-3 - 3) = 2/-6 = -1/3
Gradient of BD = (7 - 1)/(1 - -1) = 6/2 = 3
-1/3 x 3 = -1 so AC and BD are perpendicular
Midpoint of AC = ((-3 + 3)/2 , (5 + 3)/2) = (0, 4)
Midpoint of BD = ((1 + -1)/2 , (7 + 1)/2) = (0, 4)
QED