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3 years ago

7. The straight line depreciation equation for a car is

Mathematics

1 answer:

dusya [7]3 years ago

5 0

Answer:

A. -13,750

B. 22,000

Step-by-step explanation:

A. times 5

B. times 8

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The football team lost three yardsOn the first play game 5 yards on the second play in lost to yards on the third play represent

timurjin [86]

Answer:

Total lost yards = 10 yards

Step-by-step explanation:

Given:

First match = lost 3 yards

Second match = lost 5 yards

Third match = lost 2 yards

Find:

Total lost yards

Computation:

Total lost yards = First match + Second match + Third match

Total lost yards = 3 yards + 5 yards + 2 yards

Total lost yards = 10 yards

8 0

4 years ago

Jordan wants to solve the following system using the elimination method:

sergeinik [125]

Answer:

see explanation

Step-by-step explanation:

Given the 2 equations

2x + 3y = 10 → (1)

x + y = 7 → (2)

Multiplying (2) by - 3 and adding to (1) will eliminate y

- 3x - 3y = - 21 → (3)

Add (1) and (3) term by term to eliminate y, that is

- x = - 11 ( multiply both sides by - 1 )

x = 11

Substitute x = 11 into either of the 2 equations and evaluate for y

Substituting into (2)

11 + y = 7 ( subtract 11 from both sides )

y = - 4

Solution is (11, - 4 )

6 0

4 years ago

aaron tracks the time it takes him to mow lawns by writing coordinate points relating x, the time in hours it takes to mow a law

kogti [31]

The line has a positive slope of [2.5 - 1.5]/[5-3] =1/2. The the angle of lean is 26.6°.

5 0

3 years ago

Read 2 more answers

F(x)=1/4x-2 graph the function and the inverse

Oxana [17]

Answer:

Graph is below

Inverse: y=x/4 -2

y=x/4 -2

x=y/4 -2

x=y/4 -2 for y

Answer: y=4x+8

Step-by-step explanation:

8 0

3 years ago

Consider randomly selecting a student at a certain university, and let A denote the event that the selected individual

Stells [14]

Answer:

(a) P( A ∩ B )=0.5 is not possible.

(b) 0.7

(d) 0.3

(e) 0.4

Step-by-step explanation:

Given information: The alphabet A and B represents the following events

A : Individual has a Visa credit card.

B: Individual has a MasterCard.

P(A)= 0.6 and P(B)=0.4.

(a)

We need to check whether P( A ∩ B ) can be 0.5 or not.

$A\cap B\subset A$ and $A\cap B\subset B$

$P(A\cap B)\leq P(A)$ and $P(A\cap B)\leq P(B)$

$P(A\cap B)\leq 0.6$ and $P(A\cap B)\leq 0.4$

From these two inequalities we conclude that

$P(A\cap B)\leq 0.4$

Therefore, P( A ∩ B )=0.5 is not possible.

(b)

Let $P(A\cap B)=0.3$

We need to find the probability that student has one of these two types of cards.

$P(A\cup B)=P(A)+P(B)-P(A\cap B)$

Substitute the given values.

$P(A\cup B)=0.6+0.4-0.3=0.7$

Therefore the probability that student has one of these two types of cards is 0.7.

(c)

We need to find the probability that the selected student has neither type of card.

$P(A'\cup B')=1-P(A\cup B)$

$P(A'\cup B')=1-0.7=0.3$

Therefore the probability that the selected student has neither type of card is 0.3.

(d)

The event that the select student has a visa card, but not a mastercard is defined as

$A-B$

It can also written as

$A\cap B'$

The probability of this event is

$P(A\cap B')=P(A)-P(A\cap B)$

$P(A\cap B')=0.6-0.3=0.3$

Therefore the probability that the select student has a visa card, but not a mastercard is 0.3.

(e)

We need to find the probability that the selected student has exactly one of the two types of cards.

$P(A\cap B')+P(A\cap B')=P(A\cup B)-P(A\cap B)$

$P(A\cap B')+P(A\cap B')=0.7-0.3$

$P(A\cap B')+P(A\cap B')=0.4$

Therefore the probability that the selected student has exactly one of the two types of cards is 0.4.

8 0

3 years ago