Answer:
As per the statement:
Hawick is 15 miles south of Abbotsford, and Kelso is 17 miles east of Abbotsford.
Let H represents Hawick , A represents Abbotsford and K represents Kelso
See the diagram as shown below:
Distance of AH = 15 miles
Distance of AK = 17 miles.
We have to find the distance HK:
Using Pythagoras theorem;

then;

or
miles.
Therefore, the distance from Hawick to Kelso( to the nearest tenth place) is 22.6 miles
Answer:
The median and IQR
Step-by-step explanation:
bearing in mind that the slope goes by several names
average rate of change
rate of change
rise over run
deltaY over deltaX
however, is the same cat disguised with a different costume.

Answer:
B). SAS similarity.
Step-by-step explanation:
In Δ WVU & ΔCAB,
UV/CA = 17/34 = 1/2
&
VW/AB = 14/28 = 1/2
∵ UV/CA = VW/AB = 1/2
& ∠V = ∠A (Given)
∵ ΔWVU ≅ ΔCAB (by SAS similarity)