Question

Solve -3x-6>4x+8 please

Answer 1

$\bf{-3x-6 > 4x+8}$

Subtract 4x on both sides.

$\bf{-3x-6-4x > 8}$

Combine -3x and -4x to get -7x.

$\bf{-7x-6 > 8 }$

Add 6 to both sides.

$\bf{-7x > 8+6 }$

Add 8 and 6 to get 14.

$\bf{-7x > 14 }$

Divide both sides by -7. Since -7 is < 0, the inequality direction is changed.

$\bf{x < \dfrac{14}{-7} }$

Divide 14 by -7 to get -2.

$\bf{x < -2 \ \ \to \ \ \ Answer}$

$\red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}$

Answer 2

Hi student, let me help you out!

.......................................................................................................

Let's solve this inequality by following these steps:

1. Add 6 to both sides.
2. Subtract 4x from both sides.
3. Solve for x.

Step 1: Add 6 to both sides: $\pmb{-3x-6+6 > 4x+8+6}$.

Upon simplifying this, we obtain $\pmb{-3x > 4x+14}$.

Step 2. Subtract 4x from both sides: $\pmb{-3x-4x > 4x-4x+14}$.

Upon simplifying, we obtain $\pmb{-7x > 14}$.

Step 3. Divide both sides by -7.

Upon carrying this out, we obtain $\pmb{x < -2}$.

$\ddot\bigstar$ Remember this...

$\fbox{\sf{The\:sign\:of\:the\:inequality\:changes\:if\:both\:sides\:are\:divided/multiplied\:by\:a\:negative\:number}}$

Hope this helped you out, ask in comments if any queries arise.

Best Regards!

$\star\bigstar\overline{\overline{\underline{\underline{\bold{Reach\:far.\:Aim\:high.\:Dream\:big.}}}}}\bigstar\star$

$\underline{\rule{300}{5}}$