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elena-14-01-66 [18.8K]
3 years ago
9

Tell wheather the system has one solution, infinitely many solutions, or no solution.

Mathematics
1 answer:
ipn [44]3 years ago
5 0
<h3>Answer:</h3>
  1. One solution: (x, y) = (2, 0)
  2. Infinitely many solutions: 2x -5y = 17
<h3>Step-by-step explanation:</h3>

1. When you put the second equation in standard form, it is ...

... 5x +3y = 10

This is a different equation than the first one, so there will be one solution where the lines interect. (Adding the two equations gives 10x=20 ⇒ x=2. Since adding or subtracting y gives the same result, y must be zero.)

2. When you put the second equation in standard form, it is the same as the first:

... 2x -5y = 17 . . . . . divide the equation by 3

That is, any (x, y) values that satisfy the first equation will also satisfy the second equation (since they are the same). There are an infinite number of (x, y) values that do so.

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Cassandra earns $12.98 an hour working at Key Food. How much money will she
solmaris [256]

Answer:

12.98x36.7=476.366

5 0
3 years ago
How do you this question? Please explain.
Nuetrik [128]

Answer:

(C) 2√15

Step-by-step explanation:

Recognize that all the triangles are right triangles, so are similar to each other. In these similar triangles, the ratio of the short side to the long side is the same for all.

... CB/CA = CT/CB

... CB² = CA·CT = 10·6 = 60 . . . . . . . . . . multiply by CA·CB; substitute values

... CB = √60 = 2√15 . . . . . . . take the square root; simplify

_____

<em>Comment on this solution</em>

The altitude to the hypotenuse of a right triangle (CB in this case) divides the hypotenuse into lengths such that the altitude is their geometric mean. That is ...

... CB = √(AC·CT) . . . . as above

This is true for any right triangle — another fact of geometry to put in your list of geometry facts.

3 0
2 years ago
What is (0,6] n (6,8]?
Anastaziya [24]

Answer:

(6) the letter n : intersection which means the number you will find at the first bracket and has the same number at the other bracket

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cboxed%7B%5Cboxed%7B%20%5Cbegin%7Barray%7D%7B%7D%5Clarge%5Ctt%20The%20%20%5C%5C%20%20%5Ct
larisa86 [58]

Distance formula

\boxed{\sf \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}

Now

#1

\\ \tt\Rrightarrow AB=\sqrt{(3-3)^2+(-2-8)^2}=\sqrt{100}=10units

#2

\\ \tt\Rrightarrow OK=\sqrt{(5-7)^2+(-2+2)^2}=\sqrt{4}=2units

#3

\\ \tt\Rrightarrow LM=\sqrt{(-4-4)^2+(6+4)^2}=\sqrt{64+100}=\sqrt{164}\approx 13units

#4

\\ \tt\Rrightarrow PC=\sqrt{(5-2)^2+(1-3)^2}=\sqrt{9+4}=\sqrt{13}=3.2units

#5

\\ \tt\Rrightarrow QR=\sqrt{(-2+10)^2+(3-9)^2}=\sqrt{64+36}=\sqrt{100}=10units

8 0
2 years ago
Read 2 more answers
Bodmas 6x (3+8) -8x(6-2)​
Leona [35]
If your looking for the answer then it’s 34
4 0
3 years ago
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