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2 years ago

Need help with my problem of the day it’s confusing I’m not good at math :| HELP

Mathematics

1 answer:

alex41 [277]2 years ago

4 0

Answer:

7:36

Step-by-step explanation:

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Mitch is buying candy bars for his friends. He wants to give 2 bars to each friend, and he wants to have 10 spare bars. He can a

Olenka [21]

The answer is 2.2f-10=16

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2 years ago

Problem<br> 1<br> + 10x + 13 = 4

lutik1710 [3]

Answer:

$x = -1$

Step-by-step explanation:

Equation: $1+10x+13=4$

Step 1: Balance both parts of the equation.

$1+10x+13=4$

$(10x)+(1+13)=4$

$10x+14=4$

Step 2: Reduce 14 from both parts of the equation.

$10x+14-14=4-14$

$10x= -10$

Step 3: Split both sides by 10, because $\mathrn {10x = -10}$ .

$\frac{10x}{10} = \frac{-10}{10}$

$10 / -10 = -1$

Therefore, x = -1.

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2 years ago

What is x + y = 12 if x = 2y

Crazy boy [7]

I believe the answer is 4.

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2 years ago

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Please help ( angles )

svlad2 [7]

Answer: 55%

Step-by-step explanation: 100%-45%=55%

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2 years ago

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during a softball game kay hit a fly ball the function f(x) = -16t^2 + 64t + 4 describes the height of the softball in feet. mak

STatiana [176]

<h2>Hello!</h2>

The graph is attached.

To graph a parabola we need to know the following:

- If the parabola is open upwards or downwards

- They axis intercepts (if they exist)

- The vertex position (point)

We are given the function:

$f(t)=-16t^{2}+64t+4$

Where,

$a=-16\\b=64\\c=4$

For this case, the coefficient of the quadratic term (a) is negative, it means that the parabola opens downwards.

Finding the axis interception points:

Making the function equal to 0, we can find the x-axis (t) intercepts, but since the equation is a function of the time, we will only consider the positive values, so:

$f(t)=-16t^{2}+64t+4\\0=-16t^{2}+64t+4\\-16t^{2}+64t+4=0$

Using the quadratic equation:

$\frac{-b+-\sqrt{b^{2}-4ac } }{2a}=\frac{-64+-\sqrt{64^{2}-4*-16*4} }{2*-16}\\\\\frac{-64+-\sqrt{64^{2}-4*-16*4} }{2*-16}=\frac{-64+-\sqrt{4096+256} }{-32}\\\\\frac{-64+-\sqrt{4096+256} }{-32}=\frac{-64+-(65.96) }{-32}\\\\t1=\frac{-64+(65.96) }{-32}=-0.06\\\\t2=\frac{-64-(65.96) }{-32}=4.0615$

So, at t=4.0615 the height of the softball will be 0.

Since we will work only with positive values of "x", since we are working with a function of time:

Let's start from "t" equals to 0 to "t" equals to 4.0615.

So, evaluating we have:

$f(0)=-16(0)^{2}+64(0)+4=4\\\\f(1)=-16(1)^{2}+64(1)+4=52\\\\f(2)=-16(2)^{2}+64(2)+4=68\\\\f(3)=-16(3)^{2}+64(3)+4=52\\\\f(4.061)=-16(4.0615)^{2}+64(4.0615)+4=0.0034=0$

Finally, we can conclude that:

- The softball reach its maximum height at t equals to 2. (68 feet)

- The softball hits the ground at t equals to 4.0615 (0 feet)

- At t equals to 0, the height of the softball is equal to 4 feet.

See the attached image for the graphic.

Have a nice day!

3 0

2 years ago