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lianna [129]
2 years ago
6

30 people are running for an office to be chosen randomly. You plan to use a 6-sided dice and a spinner. How many sections need

to be on the spinner so each person has their own shape and number?
Select one:

a.
8


b.
6


c.
5


d.
24
Mathematics
1 answer:
allsm [11]2 years ago
3 0

The number of sections on the spinner so that each person has heir own shape and number is 5

<h3>How to determine the number of sections?</h3>

The given parameters are:

People, n = 30

Die = 6 sided

Let the sections on the spinner be s.

The equation to calculate s is represented as:

People = Die * s

This gives

30 = 6 * s

Divide both sides by 6

s = 5

Hence, the number of sections on the spinner so that each person has heir own shape and number is 5

Read more about spinners at:

brainly.com/question/24855677

#SPJ1

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Step-by-step explanation:

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How do I solve this??
pshichka [43]
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3 years ago
16.4.57 Question Help A box contains eighteen $1 bills, ten $5 bills, eight $10 bills, three $20 bills, and one $100 bill You bl
Rudiy27

Answer:

$ 7.7

Step-by-step explanation:

Given,

There are 18 $1 bills, ten $5 bills, eight $10 bills, three $20 bills, and one $100 bill,

Total number of bills = 18 + 10 + 8 + 3 + 1 = 40,

\because \text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}

Thus,

The probability of $ 1 = \frac{18}{40}

The probability of $ 5 = \frac{10}{40}

The probability of $ 10 = \frac{8}{40}

The probability of $ 20 = \frac{3}{40}

The probability of $ 100 = \frac{1}{40}

If a bill is selected randomly,

The expected value of the bill

=\frac{18}{40}\times 1+\frac{10}{40}\times 5+\frac{8}{40}\times 10+\frac{3}{40}\times 20+\frac{1}{40}\times 100

=\frac{18+50+80+60+100}{40}

=\frac{308}{40}

= $ 7.7

5 0
3 years ago
Can you please help me
kirill [66]

Answer:

b

Step-by-step explanation:

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