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Anestetic [448]
2 years ago
14

Please help i don't understand!

Mathematics
1 answer:
Maksim231197 [3]2 years ago
5 0

Answer:

Step-by-step explanation:

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Please solve these questions​
balu736 [363]

Step-by-step explanation:

x² + 4x + 3

(x+1)(x+3)

...... .

3 0
4 years ago
Um would someone help please? Only 34 and 38​
Anni [7]

Answer:

The number of students in order from least to greatest is 14<24<27<54

Step-by-step explanation:

Total students = 150

16% students play soccer

No. of students play soccer = 

9/25 play basketball

No. of students play basketball = 

 play football

No. of students play football = 

No. of students do not play anything = 14

The number of students in order from least to greatest is 14<24<27<54

7 0
3 years ago
2x+8y= 6 over<br> 5x+20y=15
garik1379 [7]

Answer:

Infinitely many solutions

Step-by-step explanation:

2x+8y=6

5x+20y=15

------------------

simplify 2x+8y=6 into x+4y=3

simplify 5x+20y=15 into x+4y=3

------------------------

infinitely many solutions

3 0
4 years ago
ASAP! I NEED THIS DONE AS QUICKLY AS POSSIBLE WITH WORKING OUT
Elza [17]

Answer:

See explanation.

Step-by-step explanation:

Let us first analyze some principle theory. By definition we know that the velocity ( v ) is a function of a distance  ( d ) covered in some time  ( t ), whilst acceleration ( a ) is the velocity achieved in some time. These can also been expressed as:

v = \frac{d}{t}\\ and a=\frac{v}{t}

We also know that both velocity and acceleration are vectors (therefore they are characterized by both a magnitude and a direction). Finally we know that given a position vector we can find the <u>velocity and the acceleration</u>, by differentiating the vector with respect to time, once and twice, respectively.

Let us now solve our problem. Here we are givine the Position vector of a particle P (in two dimensional space of i-j ) as:

r=(3t^3-t+3)i+(2t^2+2t-1)j         Eqn.(1)

Let us solve.

<u>Part (a) Velocity: </u><u>we need to differentiate Eqn.(1) with respect to time as:</u>

v(t)=\frac{dr}{dt}\\\\ v(t)=[(3)3t^2-1]i+[(2)2t+2]j\\\\v(t)=(9t^2-1)i+(4t+2)j            Eqn.(2)

<u>Part (b) Acceleration: </u><u>we need to differentiate Eqn.(2) with respect to time as:</u>

<u />a(t)=\frac{dv}{dt}\\ \\a(t)=[(2)9t]i+4j\\\\a(t)=(18t)i+4j<u />

<u />

Thus the expressions for the velocity and the acceleration of particle P in terms of t are

v(t)=(9t^2-1)i+(4t+2)j   and   a(t)=(18t)i+4j

6 0
4 years ago
Quqwywteevsbzk,skksmkjmdncnhjck,xjalb
lys-0071 [83]

Answer:

Step-by-step explanation:

6 0
3 years ago
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