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2 years ago

Question 3 of 10

Chemistry

1 answer:

Darya [45]2 years ago

8 0

The pOH of a solution with [OH] = 9.0 × 107 will be D (6.04).

<h3>What is ph value?</h3>

A ph value is the measure of acidity and the basics of a substance or solution.

Given;

[OH] = 9.0 × 10^7

pOH = - log [OH⁻]

pOH = - log (9.0 x 10⁻⁷)

pOH = 6.0457

Hence, The pOH of a solution with [OH] = 9.0 × 107 will be D (6.04).

Learn more about ph value here;

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Which type of bond is MOST LIKELY formed in nitrous oxide?

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The type of bond most likely formed in nitrous oxide would be a covalent bond..

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To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple _______. Then, plot ln(K

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Answer:

To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us use the thermodynamic definition of the Gibbs free energy and its relationship with Ksp as follows:

$\Delta G=-RTln(Ksp)\\\\\Delta G=\Delta H-T\Delta S$

Thus, by combining them, we obtain:

$-RTln(Ksp)=\Delta H-T\Delta S\\\\ln(Ksp)=-\frac{\Delta H}{RT} +\frac{T\Delta S}{RT} \\\\ln(Ksp)=-\frac{\Delta H}{RT} +\frac{\Delta S}{R}$

Which is related to the general line equation:

$y=mx+b$

Whereas:

$y=ln(Ksp)\\\\m=-\frac{\Delta H}{R} \\\\x=\frac{1}{T} \\\\b=\frac{\Delta S}{R}$

It means that we answer to the blanks as follows:

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3 years ago

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If a gas has a volume of 15l and a temperature of 125K, and the temperature is increased to 225K, what is the new volume

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Answer:

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Explanation:

Given data:

Initial volume = 15 L

Initial temperature = 125 K

Final temperature = 225 K

Final volume = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁

V₂ = 15 L × 225K / 125 k

V₂ = 3375 L.K / 125 K

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3 years ago

Now let us refine our model by noting that there is a second source of Na+ ions in the cell: NaI. Suppose the outside of the cel

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Explanation:

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Considering the given information, the new concentration of Na+inside will be (13.6 + 4) mM = 17.6 mM, and outside will be (150 + 0.04) mM = 150.04 mM due to the previous specified conditions.

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