Answer:
13.2 g of gold
Explanation:
We'll begin by converting 5.25 L to ft³.
This can be obtained as follow:
Recall:
1 L = 0.0353 ft³
Therefore,
5.25 L = 5.25 × 0.0353
5.25 L = 1.85×10¯¹ ft³
From the question given above,
2.45 g of gold is present in 5.25 L ( i.e 1.85×10¯¹ ft³) of soil.
Therefore, Xg of gold will be present in 1 ft³ of soil i.e
Xg of gold = 2.45/1.85×10¯¹
Xg of gold = 13.2 g
Therefore, 13.2 g of gold is present in 1 ft³ of the soil.
Combustion reaction
Key: O2
O2 is normally in a chemical formula when you are used to burn anything, so basically, anything with O2 involves burning.
Your weight is a measure of ibs/pounds
Hey there,
I hope this answer solves your doubt.
<u>S</u><u>t</u><u>e</u><u>p</u><u>-</u><u>b</u><u>y</u><u>-</u><u>s</u><u>t</u><u>e</u><u>p</u><u> </u><u>Expla</u><u>n</u><u>a</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u>
The question is asking if the bonds between Carbon and Chlorine in CCl4 will be single, double or triple bonds.
<em>(</em><em>The structure of CCl4 </em><em>i</em><em>s attached as picture. Check it</em><em>)</em>
As per image, the structure consists of <u>Singl</u><u>e</u><u> </u><u>b</u><u>o</u><u>n</u><u>d</u><u>s</u><u>.</u> It is <u>4 single bonds</u>.
Answer:
im not sure
Explanation:
i went on here looking nobody answered yet