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Kipish [7]
2 years ago
11

(1) (a) In an equilibrium reaction between gases Q2 and R2 to form QR, the energy content of the reactants is 100KJ and that of

the product is 54KJ. The energy content of the activated complex is 210KJ. (i) Draw an energy profile diagram for the reaction. (ii) Determine the: I. activation energy of the reaction. II. enthalpy change A H of the reaction. (iii) Write a balanced equation for the reaction. (iv) State whether the reaction is exothermic or endothermic. (v) Give a reason for the answer given in 1(a)(iv). (b) (i) If sodium reacts with cold water, state ONE observation that would be made as the reaction Proceeds. (ii) Write a balanced chemical equation for the reaction in 1(a)(i) (iii) Calculate the volume of gas produced at s.t.p if 3.0g of sodium reacts with excess water. [Molar volume of gas at s.t.p = 22.4dm³; H = 1.0, O=16.0, Na = 23.0] (c) Name ONE allotrope of oxygen.​
Chemistry
1 answer:
andrezito [222]2 years ago
7 0

Answer:

a is my answer

Explanation:

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MatroZZZ [7]

Answer:

d. decomposition

Explanation:

decomposition reaction is a reaction in which a compound breaks down into 2 or more substances.

the general form is: AB → A + B

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What class of compounds do fats belong to
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Fats are referred to as lipids, or cellular compounds that are insoluble in water.
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Write the net ionic equ.
Artyom0805 [142]

Answer:

a) AgNO3 + KI → AgI + KNO3

b) Ba(OH)2 + 2HNO3 → Ba(NO3)2 + 2H2O

c) 2Na3PO4  + 3Ni(NO3)2  → Ni3(PO4)2 + 6NaNO3

d) 2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O

Explanation:

a) AgNO3 + KI → Ag+ + NO3- + K+ + I-

Ag+ + NO3- + K+ + I-  → AgI + KNO3

AgNO3 + KI → AgI + KNO3

b) Ba(OH)2 + 2HNO3 → Ba^2+ + 2OH- + 2H+ + 2NO3-

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Ba(OH)2 + 2HNO3 → Ba(NO3)2 + 2H2O

c) 2Na3PO4  + 3Ni(NO3)2 → 6Na+ + 2PO4^3- + 3Ni^2+ + 6NO3-

6Na+ + 2PO4^3- + 3Ni^2+ + 6NO3- →  Ni3(PO4)2 + 6NaNO3

2Na3PO4  + 3Ni(NO3)2  → Ni3(PO4)2 + 6NaNO3

d) 2Al(OH)3 + 3H2SO4 → 2Al^3+ + 6OH- + 6H+ + 3SO4^2-

2Al^3+ + 3OH- + 3H+ + 3SO4^2- → Al2(SO4)3 + 6H2O

2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O

7 0
3 years ago
The pressure of a sample of helium is 1.556 atm in a 268.5 mL container. If the container is compressed to 112.4 mL without chan
Rainbow [258]

Answer:

a.  3.72 [atm]

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(1.556[atm])(268.5[mL])=P_2(112.4[mL])

\dfrac{(1.556[atm])(268.5[mL\!\!\!\!\!\!\!\!{--}])}{112.4[mL \!\!\!\!\!\!\!\!{--}]}=\dfrac{P_2(112.4[mL]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{-----})}{112.4[mL]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{-----}}

3.716957[atm]=P_2

It seems like the answer should have 4 significant figures since all of the other quantities have 4 significant figures, but the closest answer choice of those provided is a.  3.72

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Give an example of radiation?
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Microwave, light from a candle, xrays, uv light from the sun
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