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Kipish [7]
2 years ago
11

(1) (a) In an equilibrium reaction between gases Q2 and R2 to form QR, the energy content of the reactants is 100KJ and that of

the product is 54KJ. The energy content of the activated complex is 210KJ. (i) Draw an energy profile diagram for the reaction. (ii) Determine the: I. activation energy of the reaction. II. enthalpy change A H of the reaction. (iii) Write a balanced equation for the reaction. (iv) State whether the reaction is exothermic or endothermic. (v) Give a reason for the answer given in 1(a)(iv). (b) (i) If sodium reacts with cold water, state ONE observation that would be made as the reaction Proceeds. (ii) Write a balanced chemical equation for the reaction in 1(a)(i) (iii) Calculate the volume of gas produced at s.t.p if 3.0g of sodium reacts with excess water. [Molar volume of gas at s.t.p = 22.4dm³; H = 1.0, O=16.0, Na = 23.0] (c) Name ONE allotrope of oxygen.​
Chemistry
1 answer:
andrezito [222]2 years ago
7 0

Answer:

a is my answer

Explanation:

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4 years ago
RATE LAW QUESTION !
vivado [14]
In general, we have this rate law express.:

\mathrm{Rate} = k \cdot [A]^x [B]^y
we need to find x and y

ignore the given overall chemical reaction equation as we only preduct rate law from mechanism (not given to us).

then we go to compare two experiments in which only one concentration is changed

compare experiments 1 and 4 to find the effect of changing [B]
divide the larger [B] (experiment 4)  by the smaller [B] (experiment 1) and call it Δ[B]

Δ[B]= 0.3 / 0.1 = 3

now divide experiment 4 by experient 1 for the given reaction rates, calling it ΔRate:

ΔRate = 1.7 × 10⁻⁵ / 5.5 × 10⁻⁶ = 34/11 = 3.090909...

solve for y in the equation \Delta \mathrm{Rate} = \Delta [B]^y

3.09 = (3)^y \implies y \approx 1

To this point, \mathrm{Rate} = k \cdot [A]^x [B]^1

do the same to find x.
choose two experiments in which only the concentration of B is unchanged:

Dividing experiment 3 by experiment 2:
Δ[A] = 0.4 / 0.2 = 2
ΔRate = 8.8 × 10⁻⁵ / 2.2 × 10⁻⁵ = 4

solve for x for \Delta \mathrm{Rate} = \Delta [A]^x

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6 0
3 years ago
The transfer of heat energy that does not require matter of any type is _____.
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6 0
3 years ago
Read 2 more answers
How many grams of sodium (na ) would be needed to create a 100 millimole concentration in one liter?
Rina8888 [55]

2.3g of sodium would be needed to create a 100 millimole concentration in one liter.

Given,

Mole of Na+ = 100 millimole

As we know that,

1 millimole = 10 -³ mole

Mole of Na+ in 100 millimoles = 100 × 10 -³ mole

= 0.1mole

<h3>What is Mole? </h3>

Mole is defined as the ratio of mass of Na+ to the molar mass of sodium.

<h3>What is Molar Mass? </h3>

The molar mass is defined as the sum of the total mass in grams unit of the atoms present to make a molecule per mole.

Mole of Na+ = mass of Na + / molar mass of Na +

0.1 = mass of Na + / 22.99 gl mol

Mass of Na + = 0.1 × 22.99

= 2.299 g

Mass of Na + = 2.3 g

Thus, we calculated that 2.3g of sodium would be needed to create a 100 millimole concentration in one liter.

learn more about moles:

brainly.com/question/15209553

#SPJ4

7 0
2 years ago
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