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Kipish [7]
2 years ago
11

(1) (a) In an equilibrium reaction between gases Q2 and R2 to form QR, the energy content of the reactants is 100KJ and that of

the product is 54KJ. The energy content of the activated complex is 210KJ. (i) Draw an energy profile diagram for the reaction. (ii) Determine the: I. activation energy of the reaction. II. enthalpy change A H of the reaction. (iii) Write a balanced equation for the reaction. (iv) State whether the reaction is exothermic or endothermic. (v) Give a reason for the answer given in 1(a)(iv). (b) (i) If sodium reacts with cold water, state ONE observation that would be made as the reaction Proceeds. (ii) Write a balanced chemical equation for the reaction in 1(a)(i) (iii) Calculate the volume of gas produced at s.t.p if 3.0g of sodium reacts with excess water. [Molar volume of gas at s.t.p = 22.4dm³; H = 1.0, O=16.0, Na = 23.0] (c) Name ONE allotrope of oxygen.​
Chemistry
1 answer:
andrezito [222]2 years ago
7 0

Answer:

a is my answer

Explanation:

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Ilia_Sergeevich [38]
<span>Answer: has only one identity

Compounds like water (H2O) has 2 kinds of atoms which are hydrogen and oxygen. They also have a chemical bond and their bond is not able to be separated by physical means. It different with a mixture of water with sugar. The water and sugar are two different molecules but they don't bind each other. If you evaporate the water, the sugar will remains so it </span>can be separated by physical means.<span>.</span>
3 0
3 years ago
What is the volume of an object whose dimensions are 5.54 cm, 10.6 cm, and 199 cm? Round your answer to the correct number of si
Akimi4 [234]

Answer:

D. 11686.076 cm^3.

Explanation:

Assuming that this is a prism the volume is:

5.54 * 10.6 * 199

= 11686.076 cm^3.

8 0
3 years ago
What have scientists been able to use to create the Geologic Time Scale?
dem82 [27]
The half-life of the carbon-14 isotope is used in dating fossils in a process called radiocarbon dating.

hope this is adequate. 
3 0
3 years ago
Need help with this science question..
natali 33 [55]

Answer:no

Explanation:the heat will add more pressureand then it will pop.

5 0
3 years ago
If you have access to stock solutions of 1.00 M H3PO4, 1.00 M of HCl, and 1.00 M NaOH solution, (and distilled water of course),
garri49 [273]

Answer:

0.10L of 1.00M of H₃PO₄ and 0.1613L of 1.00M NaOH

Explanation:

The pKa's of phosphoric acid are:

H₃PO₄/H₂PO₄⁻ = 2.1

H₂PO₄⁻/HPO₄²⁻ = 7.2

HPO₄²⁻/PO₄³⁻ = 12.0

To make a buffer with pH 9.40 we need to convert all H₃PO₄ to H₂PO₄⁻ and an amount of H₂PO₄⁻ to HPO₄²⁻

To have a 50mM solution of phosphoures we need:

2L * (0.050mol / L) = 0.10 moles of H₃PO₄

0.10 mol * (1L / mol) = 0.10L of 1.00M of H3PO4

To convert the H₃PO₄ to H₂PO₄⁻ and to HPO₄²⁻ must be added NaOH, thus:

H₃PO₄ + NaOH → H₂PO₄⁻ + H₂O + Na⁺

H₂PO₄⁻ + NaOH → HPO₄²⁻ + H₂O + Na⁺

Using H-H equation we can find the amount of NaOH added:

pH = pKa + log [A⁻] / [HA] <em>(1)</em>

<em>Where [A-] is conjugate base, HPO₄²⁻ and [HA] is weak acid, H₂PO₄⁻</em>

<em>pH = 7.40</em>

<em>pKa = 7.20</em>

[A-] + [HA] = 0.10moles <em>(2)</em>

Replacing (2) in (1):

7.40 = 7.20 + log 0.10mol - [HA] / [HA]

0.2 = log 0.10mol - [HA] / [HA]

1.5849 = 0.10mol - [HA] / [HA]

1.5849 [HA] = 0.10mol - [HA]

2.5849[HA] = 0.10mol

[HA] = 0.0387 moles = H₂PO₄⁻ moles

That means moles of HPO₄²⁻ are 0.10mol - 0.0387moles = 0.0613 moles

The moles of NaOH needed to convert all H₃PO₄ in H₂PO₄⁻ are 0.10 moles

And moles needed to obtain 0.0613 moles of HPO₄²⁻ are 0.0613 moles

Total moles of NaOH are 0.1613moles * (1L / 1mol) = 0.1613L of 1.00M NaOH

Then, you need to dilute both solutions to 2.00L with distilled water.

4 0
3 years ago
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