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2 years ago

Im still confused on how to use the distance formula

Mathematics

1 answer:

notsponge [240]2 years ago

5 0

Answer:

The distance formula is a formula that is used to find the distance between two points. These points can be in any dimension.

The formula for it is:

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PLEASE HELP ME I don’t get it

Temka [501]

Split the figure into 3 shapes: a trapezoid,a rectangle and a triangle

Area of trapezoid

A= 1/2(b1+b2) h

A = 1/2(3 +9)(8)

A = 1/2(12)(8)

A = 48 square units

Area of rectangle:

A = L x W

A = 9 x 8

A = 72 square units

Area of triangle

A = 1/2bh

A = 1/2(3)(8)

A = 12 square units

Area of figure = 48 square units + 72 square units + 12 square units

= 132 square units

Answer

132 square units

4 0

3 years ago

Please help me!!!!!

Bas_tet [7]

Answer: see proof below

<u>Step-by-step explanation:</u>

Use the Sum & Difference Identity: tan (A - B) = (tanA - tanB)/(1 + tanA tanB)

Use the Half-Angle Identity: tan (A/2) = (1 - cosA)/(sinA)

Use the Unit Circle to evaluate tan (π/4) = 1

Use Pythagorean Identity: cos²A + sin²A = 1

<u>Proof LHS → RHS</u>

$\text{Given:}\qquad \qquad \qquad\dfrac{2\tan\bigg(\dfrac{\pi}{4}-\dfrac{A}{2}\bigg)}{1+\tan^2\bigg(\dfrac{\pi}{4}-\dfrac{A}{2}\bigg)}$

$\text{Difference Identity:}\qquad \dfrac{2 \bigg( \frac{\tan\frac{\pi}{4}-\tan\frac{A}{2}}{1+\tan\frac{\pi}{4}\cdot \tan\frac{A}{2}}\bigg)}{1+ \bigg( \frac{\tan\frac{\pi}{4}-\tan\frac{A}{2}}{1+\tan\frac{\pi}{4}\cdot \tan\frac{A}{2}}\bigg)^2}$

$\text{Substitute:}\qquad \qquad \dfrac{2 \bigg( \frac{1-\tan\frac{A}{2}}{1+\tan\frac{A}{2}}\bigg)}{1+ \bigg( \frac{1-\tan\frac{A}{2}}{1+\tan\frac{A}{2}}\bigg)^2}$

$\text{Simplify:}\qquad \qquad \qquad \dfrac{1-\tan^2\frac{A}{2}}{1+\tan^2\frac{A}{2}}$

$\text{Half-Angle Identity:}\qquad \quad \dfrac{1-(\frac{1-\cos A}{\sin A})^2}{1+(\frac{1-\cos A}{\sin A})^2}$

$\text{Simplify:}\qquad \qquad \dfrac{\sin^2 A-1+2\cos A-\cos^2 A}{\sin^2 A+1-2\cos A+\cos^2 A}$

$\text{Pythagorean Identity:}\qquad \qquad \dfrac{1-\cos^2 A-1+2\cos A}{2-2\cos A}$

$\text{Simplify:}\qquad \qquad \qquad \dfrac{2\cos A-2\cos^2 A}{2(1-\cos A)}\\\\.\qquad \qquad \qquad \qquad =\dfrac{2\cos A(1-\cos A)}{2(1-\cos A)}$

= cos A

LHS = RHS: cos A = cos A $\checkmark$

4 0

3 years ago

I need help with this. ASAP

Margaret [11]

The answer in 4,000.

4 0

3 years ago

Read 2 more answers

1, 5, 17, 53, ... Use inductive reasoning to create a general rule for the sequence. A. Multiply by 3, then add 2. B. Multiply b

Basile [38]

The answer to this problem is the letter "A" which is "Multiply by 3, then add 2"
and can be written a N = 3n + 2
At first, we have initial value such n = 1
Then the second value is:
N = 3*1 + 2
N = 5
The third value is:
N = 3*5 + 2
N=17
The next values are:
N = 3*17 + 2
N= 53
The letter "A" is the inductive reasoning to the given sequence.

6 0

2 years ago

Find the slope of the line that passes through (8,9) and (5, 14).

AleksAgata [21]

Answer:

6/-4 (right 6 points on x-axis & down 4 points on y- axis

Step-by-step explanation:

14- 8 6

---------- = ------

5-9 - 4

7 0

2 years ago