Question

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Answer 1

Answer:

$AB=12\sqrt{3}\ cm$

Step-by-step explanation:

If AB is tangent to the circle, then angle ABO is right angle and triangle AOB is special $30^{\circ}-60^{\circ}-90^{\circ}$ triangle. In this triangle, the leg that is opposite to the angle of 30° is half of the hypotenuse. Thus,

$AO=2BO=2\cdot 12=24\ cm.$

By the Pythagorean theorem,

$AB^2=AO^2-BO^2,\\ \\AB^2=24^2-12^2,\\ \\AB^2=576-144=432,\\ \\AB=12\sqrt{3}\ cm.$