Given the function f (x) = 3x, find the value of f-1 (81).
For this case, the first thing you should do is rewrite the function.
We have then:
y = 3 ^ x
From here, we clear the value of x:
log3 (y) = log3 (3 ^ x)
log3 (y) = x
Then, we rewrite the function again:
f (x) ^ - 1 = log3 (x)
Now, we evaluate the inverse function for x = 81:
f (81) ^ - 1 = log3 (81)
f (x) ^ - 1 = 4
Answer:
the value of f-1 (81) is:
f (x) ^ - 1 = 4
We have to determine the complete factored form of the given polynomial
.
Let x= -1 in the given polynomial.
So, 
So, by factor theorem
(x+1) is a factor of the given polynomial.
So, dividing the given polynomial by (x+1), we get quotient as
.
So,
= (x+1)
.
= 
=![(x+1)[ 2x(3x-5)-3(3x-5)]](https://tex.z-dn.net/?f=%28x%2B1%29%5B%202x%283x-5%29-3%283x-5%29%5D)
=
is the completely factored form of the given polynomial.
Option D is the correct answer.
Equating the formula (d is the diameter)

d^2/4 = 132.7
d^2 = 132.7*4/

d =

d = 13.0017147331
d= 13cm
I got 1,727,940
Plug in the numbers
Answer: x = 4
Step-by-step explanation:
3x - 11 + 9 = 10
Add 11 to each side
3x + 9 = 21
Subtract 9 from each side
3x = 12
Divide each side by 3
x = 4