For f(x)=1/x^2-3
Find
A) f(3)
B) f(2-h)
If f(x)=1/x^2-3, then f(3) = 1 / 3^2 - 3. The exponentiation here must be carried out first: f(3) = 1/9 - 3. Then f(3) = 1/9 - 27/9 = -26/9
If f(x)=1/x^2-3, then f(2-h) = 1 / [2-h]^2 - 3. This result may be left as is or expanded. In expanded form, we have:
1
f(2-h) = ------------------ - 3
4-4h +h^2
The answer is B. -7m+12.
First distribute the -2 to 6m and -5.
5m-2(6m-5)+2
5m+(-2*6m)+(-2*-5)+2
5m+-12m+10+2
After that, combine the like terms.
5m+-12m+10+2
-5m+-12m=-7m
10+2=12
The simplified expression is -7m+12.
9x-20=7
9x=27
x=3
Hope that helps you :)
Answer:
An isosceles triangle
Step-by-step explanation:
An isosceles triangle has 3 sides and has two equivalent sides with the same measure
