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Ratling [72]
2 years ago
14

3. A body accelerates constantly at 4m/s² from rest for a distance of 60m. a) How long did it take to reach a distance of 60m? [

2] b) Calculate the velocity reached.​
Physics
1 answer:
d1i1m1o1n [39]2 years ago
5 0

Answer:

will you mark brainliest.

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Hanging from a horizontal beam are nine simple pendulums of the following lengths: (a) 0.080, (b) 0.26, (c) 0.49, (d) 0.90, (e)
mote1985 [20]

Answer:

Explanation:

This is the case of forced oscillation . The pendulum having the same or matching time period  or angular frequency with that of angular frequency  of external periodic force , will be in resonance having largest amplitude.

Angular frequency of pendulum having length .9 m

= \sqrt{\frac{g}{l } }

l = .9

angular frequency

= \sqrt{\frac{10}{0.9 } }

= 3.33 rad / s

If we calculate angular frequencies of pendulum of all lengths given , we will find that other lengths do not give angular frequency falling between 2 and 4 radian . So only pendulum having length of .9 m will have vibration of maximum amplitude.

8 0
3 years ago
Unit of energy density of electric field is a) NC-3 b) JC-3 c) Jm-3 d)JF
erik [133]

Answer:

the answer is c

8 0
4 years ago
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A force of 120 N is acting on a surface of area 100 cm 2 . Calculate the pressure acting on the surface.
defon

Answer:

Thrust is the force acting normally to a surface. So, Thrust = 1200 N. And , Pressure = Thrust / Area. = 1200 / 0.001. = ...

Explanation:

this right like me

6 0
3 years ago
Predict whether the changes in enthalpy, entropy, and free energy will be positive or negative for the melting of ice, and expla
BlackZzzverrR [31]
  <span>Melting of ice is an endothermic process, meaning that energy is absorbed. When ice spontaneously melts, ΔH (change in enthalpy) is "positive". ΔS (entropy change) is also positive, because, becoming a liquid, water molecules lose their fixed position in the ice crystal, and become more disorganized. ΔG (free energy of reaction) is negative when a reaction proceeds spontaneously, as it happens in this case. Ice spontaneously melts at temperatures higher than 0°C. However, liquid water also spontaneously freezes at temperatures below 0°C. Therefore the temperature is instrumental in determining which "melting" of ice, or "freezing" of water becomes spontaneous. The whole process is summarized in the Gibbs free energy equation: 
ΔG = ΔH – TΔS</span>
4 0
3 years ago
Consider a system consisting of an ideal gas confined within a container, one wall of which is a movable piston. Energy can be a
Helen [10]

Complete Question

Consider a system consisting of an ideal gas confined within a container, one wall of which is a movable piston. Energy can be added to the gas in the form of heat by applying a flame to the outside of the container. Conversely, energy can also be removed from the gas in the form of heat by immersing the container in ice water. Energy can be added to the system in the form of work by pushing the piston in, thereby compressing the gas. Conversely, if the gas pushes the piston out, thereby pushing some atmosphere aside, the internal energy of the gas is reduced by the amount of work done.

          pV=nRT

so the absolute temperature T is directly proportional to the product of the absolute pressure p and the volume V,Here n denotes the amount of gas moles,which is a constant because the gas is confined and R is the universal constant

What is the \triangle U as the system of ideal gas goes from point A to point B on the graph recall u is proportional to T

Answer:

\triangle T=0

\triangle V=0

The gas A and B have same internal energy

Explanation:

From the question we are told that

Pa=u atm\\Va=1m^3\\Pb=1 atm\\Vb=4m^3

Generally the equation of temperature is mathematically given as

Ta=\frac{Pv}{nR}

Ta=\frac{u*1}{nR}

And

Tb=\frac{PbVb}{nR}

Tb=\frac{u*1}{nR}

Generally the change in temperature \triangle T is mathematically given as

\triangle T=Tb-Ta=Tb=\frac{u*1}{nR}-\frac{u*1}{nR}

\triangle T=0

Generally the change in internal energy \triangle V

\triangle V=nC_v \triangle T\\

\triangle V=0

Therefore with

\triangle T=0

\triangle v=0

The gas A and B have same internal energy

6 0
3 years ago
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