Answer:
<em><u>Given: </u></em>
m1 = 7 kg
V1 = 12 m/s
m2 = 25 kg
V2 = 6 m/s
<em><u>To find:</u></em>
Combined speed of two balls stick together after collision V = ?
<em><u>Solution:</u></em>
<em>According to law of conservation of momentum,</em>
m1V1 + m2V2 = (m1+m2)V
7×12 + 25×6 = (7+25)V
84 + 150 = 32V
V = 234/32
V = 7.31 m/s
Combined speed of two ball is 7.31 m/s
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Answer:
The newton's second law states that the acceleration of an object is directly proportional to the force acting upon the object and inversely proportional to the mass
False. Bases are substances that dissociate(break down) to give off hydroxide ions in aqueous solutions. The hydroxide ions are what makes them basic.
Answer:
94.13 ft/s
Explanation:
<u>Given:</u>
= time interval in which the rock hits the opponent = 10 s - 5 s = 5 s
= distance to be moved by the rock long the horizontal = 98 yards
= displacement to be moved by the rock during the time of flight along the vertical = 0 yard
<u>Assume:</u>
= magnitude of initial velocity of the rock
= angle of the initial velocity with the horizontal.
For the motion of the rock along the vertical during the time of flight, the rock has a constant acceleration in the vertically downward direction.

Now the rock has zero acceleration along the horizontal. This means it has a constant velocity along the horizontal during the time of flight.

On dividing equation (1) by (2), we have

Now, putting this value in equation (2), we have

Hence, the initial velocity of the rock must a magnitude of 94.13 ft/s to hit the opponent exactly at 98 yards.