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Crazy boy [7]
3 years ago
6

Predict whether the changes in enthalpy, entropy, and free energy will be positive or negative for the melting of ice, and expla

in your predictions. How does temperature affect the spontaneity of this process?
Physics
1 answer:
BlackZzzverrR [31]3 years ago
4 0
  <span>Melting of ice is an endothermic process, meaning that energy is absorbed. When ice spontaneously melts, ΔH (change in enthalpy) is "positive". ΔS (entropy change) is also positive, because, becoming a liquid, water molecules lose their fixed position in the ice crystal, and become more disorganized. ΔG (free energy of reaction) is negative when a reaction proceeds spontaneously, as it happens in this case. Ice spontaneously melts at temperatures higher than 0°C. However, liquid water also spontaneously freezes at temperatures below 0°C. Therefore the temperature is instrumental in determining which "melting" of ice, or "freezing" of water becomes spontaneous. The whole process is summarized in the Gibbs free energy equation: 
ΔG = ΔH – TΔS</span>
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A 7 kg ball of clay traveling at 12 m/s collides with a 25 kg ball of clay traveling in the
ANEK [815]

Answer:

<em><u>Given: </u></em>

m1 = 7 kg

V1 = 12 m/s

m2 = 25 kg

V2 = 6 m/s

<em><u>To find:</u></em>

Combined speed of two balls stick together after collision V = ?

<em><u>Solution:</u></em>

<em>According to law of conservation of momentum,</em>

m1V1 + m2V2 = (m1+m2)V

7×12 + 25×6 = (7+25)V

84 + 150 = 32V

V = 234/32

V = 7.31 m/s

Combined speed of two ball is 7.31 m/s

<em><u>Thanks for joining brainly community!</u></em>

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2 years ago
Hi i need help re-stating Newton's Second law. It needs to be at least two sentences.
jek_recluse [69]

Answer:

The newton's second law states that the acceleration of an object is directly proportional to the force acting upon the object and inversely proportional to the mass

8 0
3 years ago
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A base is a substance that produces hydrogen ions in a water solution
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False. Bases are substances that dissociate(break down) to give off hydroxide ions in aqueous solutions. The hydroxide ions are what makes them basic.
4 0
3 years ago
Two runners start at the same point on a straight track. The first runs with constant acceleration so that he covers 98 yards in
charle [14.2K]

Answer:

94.13 ft/s

Explanation:

<u>Given:</u>

  • t = time interval in which the rock hits the opponent = 10 s - 5 s = 5 s
  • s = distance to be moved by the rock long the horizontal = 98 yards
  • y = displacement to be moved by the rock during the time of flight along the vertical = 0 yard

<u>Assume:</u>

  • u = magnitude of initial velocity of the rock
  • \theta = angle of the initial velocity with the horizontal.

For the motion of the rock along the vertical during the time of flight, the rock has a constant acceleration in the vertically downward direction.

\therefore y = u\sin \theta t +\dfrac{1}{2}(-g)t^2\\\Rightarrow 0 = u\sin \theta 5 +\dfrac{1}{2}(-9.8)\times 5^2\\\Rightarrow u\sin \theta 5 =\dfrac{1}{2}(9.8)\times 5^2......(1)\\

Now the rock has zero acceleration along the horizontal. This means it has a constant velocity along the horizontal during the time of flight.

\therefore u\cos \theta t = s\\\Rightarrow u\cos \theta 5 = 98.....(2)\\

On dividing equation (1) by (2), we have

\tan \theta = \dfrac{25}{20}\\\Rightarrow \tan \theta = 1.25\\\Rightarrow \theta = \tan^{-1}1.25\\\Rightarrow \theta = 51.34^\circ

Now, putting this value in equation (2), we have

u\cos 51.34^\circ\times  5 = 98\\\Rightarrow u = \dfrac{98}{5\cos 51.34^\circ}\\\Rightarrow u =31.38\ yard/s\\\Rightarrow u =31.38\times 3\ ft/s\\\Rightarrow u =94.13\ ft/s

Hence, the initial velocity of the rock must a magnitude of 94.13 ft/s to hit the opponent exactly at 98 yards.

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3 years ago
Which statement is true about white dwarf?
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C is the correct answer

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