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3 years ago

For a conclusion to be accepted by the scientific community, the data must be accurate, free from error, and

2 answers:

8 0

The data must be reproducible: it means that the data will be reliable and representative and not that this data would lead to one conclusion and another data would lead to another.

Data being varied, unique or surprising does not have anything to do with acceptability of the conclusion.

yanalaym [24]3 years ago

7 0

Answer:

reproducible

Explanation: edg

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Two objects, M = 15.3 ks and m = 8.29 kg are connected with an ideal string and suspended by a pulley (which rotates with no fri

Scilla [17]

Answer:

(a) 7 m/s

(b) 931 rad/s

Explanation:

Gravity would be exerting on the 2 masses

$G_1 = Mg = 15.3*9.81 = 150.093N$

$G_2 = mg = 8.29*9.81= 81.32N$

Since heavier, mass 1 (M) would be the one pulling down, while mass 2 is being pulled up.

So the net force on mass 1 is

$F = G_1 - G_2 = 68.77N$

This force would generate torque on the solid pulley

$T = FR = 68.77 * 0.0075 = 0.5158 Nm$

We can also calculate the pulley moments of inertia, with it being solid

$I = 0.5MpR^2 = 0.5*14.1*0.0075^2 = 0.000396563kgm^2$

From there we can calculate the angular acceleration of the pulley, which generates the entire system motion

$\alpha = \frac{T}{I} = \frac{0.5158}{0.000396563} = 1300.58 rad/s^2$

Since the system is moved by a distance of d = 2.5m, the pulley would have turn an angle of

$\theta = \frac{d}{R} = \frac{2.5}{0.0075} = 333 rad$

(c)The time it takes to get to this distance is

$\theta = \frac{\alpha t^2}{2}$

$t^2 = \frac{2\theta}{\alpha} = \frac{2*333}{1300.58} =0.513$

$t = \sqrt{0.513} = 0.716s$

(b)The final angular speed of the disk is

$\omega = \alpha t = 1300.58*0.716 = 931 rad/s$

(a) And so the perimeter speed of the pulley, which is also speed of mass 1 when it comes to d = 2.5 m is

$v = \omega R = 931*0.0075 \approx 7m/s$

5 0

2 years ago

A 3.53-g sample of aluminum completely reacts with oxygen to form 6.67 g of aluminum oxide. find percent composition

katrin2010 [14]

The mass percent composition of aluminum is 52.9% in aluminum oxide.

Mass of the aluminum = 3.53 g

Mass of the aluminum oxide = 6.67 g.

The mass percent of a substance is the mass of the substance divided by the mass of the compound into 100.

Aluminum reacts with oxygen to form aluminum oxide.

The overall balanced equation for the reaction is,

$Aluminum + Oxygen→Aluminum \: oxygen$

$4Al +3O _{2}→2Al _{2}O _{3}$

The mass percent composition of aluminum in the aluminum oxide is,

$Mass \: percent = \frac{ Mass \: of \: the \: substance}{ Mass \: of \: the \: compound} \times 100$

$Mass \: percent = \frac{Mass \: of \: the \: aluminum}{ Mass \: of \: the \: aluminum \: oxide } \times 100$

$Mass \: percent = \frac{3.53}{6.67 } \times 100$

= 52.9 %

Therefore, the mass percent composition of aluminum is 52.9% in aluminum oxide.

To know more about aluminum oxide, refer to the below link:

brainly.com/question/25869623

#SPJ4

7 0

1 year ago

A boat can travel 2.30 m/s in still water. If the boat points its prow directly across a stream whose current is 1.80 m/s , what

Alinara [238K]

Answer:

A boat can travel 2.30 m/s in still water. (a) If the boat points its prow directly across a stream whose current is. ... (a) What is the velocity (magnitude and direction) of the boat relative to the shore? ... The boat's velocity with respect to the shore, , is the sum of its velocity with respect to the water

Explanation:

5 0

2 years ago

A capacitor consists of two concentric cylinders. The inner cylinder has a radius of 0.001 m and the outer cylinder a radius of

AlexFokin [52]

Answer:

The capacitance is 1.75 nF

Explanation:

From the question we are given that

The inner radius is $r_{in} = 0.001$

The outer radius is $r_{out} = 0.0011 \ m$

Length of the capacitor is $L = 1m$

The dielectric constant is $Di = 2 \ for \ 0 < \phi < \pi$

The dielectric constant is $Di_2 = 4 \ for \ \pi < \phi < 2\pi$

Generally the capacitance of a capacitor can be mathematically represented as

$C = \frac{\pi \epsilon_0 Di_1 L}{ln\frac{r_{out}}{r_{in}} } + \frac{\pi \epsilon_0 Di_2L}{ln\frac{r_{out}}{r_{in}} }$

$= \frac{\pi \epsilon_0 L (Di_1 + Di_2)}{ln\frac{r_{out}}{r_{in}} }$

$= \frac{(3.142)(8.85*10^{-12})(1)(2+4)}{ln\frac{0.0011}{0.001} }$

$=1.75*10^{-9} F$

$1.75nF$

5 0

2 years ago

A trumpet player is tuning his instrument by playing an A note simultaneously with the first-chair trumpeter, who has perfect pi

KIM [24]

To develop this problem, it is necessary to apply the concepts related to Beat

The Beat is an acoustic phenomenon that is generated by two sine waves interfering with slightly different frequencies. The beat frequency is equal to the difference in the frequencies of the two original waves:

$f_{bat} = |(f_1 \pm f_B)|$