Given data
*The mass of Bruce is m_1 = 45 kg
*The initial velocity of the Bruce is u_1 = 2 m/s
*The mass of the biff is m_2 = 90 kg
*The initial velocity of the Biff is u_2 = -7 m/s
*The final velocity of the first glider is v_2 = -1 m/s
According to the law of conservation of linear momentum, the total linear momentum of a system remains constant
Applying the law of conservation of momentum as
Substitute the known values in the above expression as
Hence, the speed of the bruce knock backwards is v_1 = -10 m/s
Energy stored in the capacitor= 2.2 x 10⁻¹⁰ J
Explanation:
The energy stored in the capacitor is given by
E= 1/2 q V
E= energy stored
q= charge= 7.6 x 10⁻¹¹ C
V= potential difference=5.8 V
so energy stored= E= 1/2 (7.6 x 10⁻¹¹) (5.8)
Energy stored= 2.2 x 10⁻¹⁰ J
Answer:
25
Explanation:
magnitude and (b) direction (as an angle relative to the x axis) of the velocity
No additional force is required because it's already going downhill
Answer:
57.885.8 kg weight of the container
Explanation:
The volume of the balloon * density of water = buoyant force of balloon
volume of a sphere = 4/3 pi r^3
= 4/3 pi * (1.5)^3 = 14.14 m^3 <===balloon volume
Now, find the buoyant force on the container ALONE ....
5.8 * 2.6 * 2.8 * 1027 = 43 364 kg <===== buoyant force
Now add the buoyant force of the balloon to find the weight
43 364 + 14.14 * 1027 = 57885.8 kg
