How can tidal force from the moon affect our earth?
2 answers:
You might be interested in
Answer:
Proton’s speed, a short time later when it reaches a point of lower potential is 1.4 x 10⁵ m/s
Explanation:
Given;
initial speed of proton, u = 2.5 x 10⁵ m/s
initial potential, V = 1500 V
mass of proton = 1.67 x 10⁻²⁷ kg
Work done, W = eV= ΔK.E = ¹/₂mu²
eV = ¹/₂mu² (J)
where;
e is the charge of the proton in coulombs
V is the electric potential in volts
m is the mass of the proton in kg
u is the speed of the proton in m/s
Therefore, proton’s speed a short time later when it reaches a point of lower potential is 1.4 x 10⁵ m/s
Answer:
The pulling force F is 200 N
Explanation:
We note that the tension in a rope between two or three blocks is given by the relation;
Where we have;
m₁ → T₁ → m₂ → T₂ → m₃ → F
m₁ = 2 kg
m₂ = 4 kg
m₃ = 4 kg
T₂ = 120 N
Therefore, by substitution, gives;
2 kg → T₁ → 4 kg → 120 N → 4 kg → F
F = 120 N × (10 kg)/(6 kg) = 200 N
The pulling force F = 200 N.