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Rudik [331]
3 years ago
15

I need help with this question, please

Physics
2 answers:
Andreyy893 years ago
4 0
Calculate the kinetic energy of the ball at the bottom of the ramp, then calculate how high it needs to be in order to have that same amount of potential energy.
Burka [1]3 years ago
3 0
Ok so this is a kinetic and potential energy problem. KE= 1/2*m*v^2 and PE= mgh so we set them equal to each other and get KE=PE so 1/2mv^2=mgh so mass divers out and left with 1/2v^2 =gh so solving for h or height we get
h=(1/2v^2)/g so h= 1/2*(6.5m/s)^2/9.80m/s^2 = 2.16m in height the ball will reach.

Hope this helps! Any questions please just ask!
Please rate to help me out also! Thank you so much!!!
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nikitadnepr [17]

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2 years ago
A parallel-plate capacitor has a voltage of 391 v applied across its plates, then the voltage source is removed. what is the vol
andrezito [222]

When the capacitor is connected to the voltage, a charge Q is stored on its plates. Calling C_0 the capacitance of the capacitor in air, the charge Q, the capacitance C_0 and the voltage (V_0=391 V) are related by

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when the source is disconnected the charge Q remains on the capacitor.


When the space between the plates is filled with mica, the capacitance of the capacitor increases by a factor 5.4 (the permittivity of the mica compared to that of the air):

C=k C_0 = 5.4 C_0

this is the new capacitance. Since the charge Q on the plates remains the same, by using eq. (1) we can find the new voltage across the capacitor:

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7 0
3 years ago
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