Explanation:
Given that,
Length of the cable is 19.6 m, l = 19.6 m
Let us assume that the angle with vertical rotating pole is 63 degrees.
The total mass of a chair and its occupant is 250 kg.
(a) Let T is the tension in the cable attached to the chair. So,
(b) The centripetal acceleration acts on it such that,
Hence, this is the required solution.
Answer:
Final velocity, v = 25.3 m/s
Explanation:
Initial velocity of a locomotive, u = 19 m/s
Acceleration of the locomotive, a = 0.8 m/s²
Length of station, d = 175 m
We need to find its final velocity (v) when the nose leaves the station. It can be calculated using the third law of motion :
v = 25.31 m/s
v = 25.3 m/s
When the nose leaves the station, it will move with a velocity of 25.3 m/s. Hence, this is the required solution.
<span>So we wan't to know what is the velocity after a collision of two railroad cars, one moving to the east and the other moving to the west if m1=2000kg, v1=5m/s and m2=6000kg, v2=3m/s. We can find the solution using the law of conservation of momentum for plastic collisions that states that the momentum must remain constant before (left side of the equation) and after (right side of the equation) the collision: m1*v1+m2*v2=(m1+m2)*v. So now we simply plug in the numbers and get: 2000kg * 5m/s + 6000kg * 3m/s = (2000kg + 6000kg)*v. Now we can write: 10000 kgm/s + 18000 kgm/s = 8000kg * v. To get v, the velocity of both railroad cars after the collision we simply divide both sides of the equation with 8000 kg: so v=3.5m/s to the west. </span>
All except A. (Answer is B,C,D)
All other administrative job which helps to support and ensure that the medical services of a healthcare organization is running but are not the actual practitioner of first hand treatment to the patient physically.
Before anything, if you are lifting the Work value have to be negative, reason is because the formula to the work of the weight is:
*Photo to help you to visualize. (P = Weight Force, F = Force)
If you are lifting, you are exercising a force that opposes the Weight Force, Force up (lifting) and Weight Force down (gravity pulling).
This forms a 180 angle and the cos 180 = -1.
Well let's do the question:
Work (W) = -40 J (Joule = Kg x m^2/s^2)
(negative, explanation given)
Weight Force (P) = 10 N (Newton = kg x m/s^2)
Distance (D) = ?
W = P x d x cos theta
-> -40 = 10 x d x -1
-> -40 = -10 x d
-> d = -40/-10 (J/N)
-> d = 4 meters