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Digiron [165]
2 years ago
8

what is the equation of the line that is perpendicular to the line y=3/5x+10 and passes through the point (15,-5)

Mathematics
1 answer:
riadik2000 [5.3K]2 years ago
6 0

Answer:

y = -\frac53x + 20

Step-by-step explanation:

Hello!

A line that is perpendicular to another has an opposite-reciprocal slope.

Meaning:

  • Flip the sign (+/-)
  • Flip the fraction

The slope perpendicular to 3/5 would be -5/3.

We can solve for the y-intercept by plugging in the x and y values given from the coordinate into the equation with out new slope.

<h3 /><h3>Solve for B</h3>
  • y = -\frac53x + b
  • -5 = -\frac53(15) + b
  • -5 = -25 + b
  • 20 = b

The y-intercept of the new line is 20.

The equation is y = -\frac53x + 20

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