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Digiron [165]
2 years ago
8

what is the equation of the line that is perpendicular to the line y=3/5x+10 and passes through the point (15,-5)

Mathematics
1 answer:
riadik2000 [5.3K]2 years ago
6 0

Answer:

y = -\frac53x + 20

Step-by-step explanation:

Hello!

A line that is perpendicular to another has an opposite-reciprocal slope.

Meaning:

  • Flip the sign (+/-)
  • Flip the fraction

The slope perpendicular to 3/5 would be -5/3.

We can solve for the y-intercept by plugging in the x and y values given from the coordinate into the equation with out new slope.

<h3 /><h3>Solve for B</h3>
  • y = -\frac53x + b
  • -5 = -\frac53(15) + b
  • -5 = -25 + b
  • 20 = b

The y-intercept of the new line is 20.

The equation is y = -\frac53x + 20

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Find each probability if a die is rolled.<br> P(divisible by 4)
olga2289 [7]
When a die is rolled, there are six posible results:
1, 2, 3, 4, 5, and 6
Total number of posible results: n=6

Divisible by 4 is only the result 4
Number of favorable results: f=1

P(divisible by 4)=f/n
P(divisible by 4)=1/6
P(divisible by 4)=0.1667
P(divisible by 4)=0.1667*100%
P(divisible by 4)=16.67%

P(divisible by 4)=1/6=0.1667=16.67% 
4 0
3 years ago
I need help on Part B and C on question 2
kap26 [50]

Answer:

The answer to your question is

Part A. Archimedes grades 6 1/4 tests per day

Part B. 8 19/32 days

Part C.  6  26/29 days

Step-by-step explanation:

Part A

Total time = 6 2/5 days

Number of tests = 40 tests

Process

1.- Convert the mixed fraction to improper fraction

                 6 2/5 = (30 + 2) / 5 = 32/5

2.- Divide 40 by 32/5

                40/1  / 32/5   = (40 x 5) / (32 x 1)

                                      = 200 / 32

Simplify

                                        100 / 16 = 50/8 = 25/4

3.- Convert 25/4 to mixed fractions

                                       6      

                                4   25            

                                        1

                   25/4 = 6 1/4

Archimedes grade 6 1/4 tests per day

Part B

15 more tests

Total time = 32/5

Total tests = 40 + 15 = 55

Process

1.- Divide 55 by 32/5

                                  55 / 1  /  32 /5    = (55 x 5) / (32 x 1)

                                                             = 275 / 32

                                                             

2.- Convert 275/32 to a mixed fraction

                                                 8                                  

                                      32   275

                                             256

                                                19

Result    8 19/32 days

Part C

1.- Divide 55 by 7.25

                                         50 / 7.25     =    5000 / 725

                                                  6

                                725    5000

                                        - 4350

                                            650    

Result 6 650/750 = 6  26/29

3 0
3 years ago
Hi algebra is hard please help: The expression (8x+ 4) inches represents the perimeter of a rectangle whose width is (3x − 4) in
Bess [88]

Answer:

Length = 4 inches

Step-by-step explanation:

Perimeter of a rectangle = 2(length + width)

If x = 2

Perimeter = 8x - 4

= 8(2) - 4

= 16 - 4

= 12 inches

Width = 3x - 4

= 3(2) - 4

= 6 - 4

= 2 inches

Perimeter of a rectangle = 2(length + width)

12 = 2(length + 2)

12 = 2length + 4

12 - 4 = 2 length

8 = 2 length

Length = 8/2

Length = 4 inches

8 0
3 years ago
MATH HELP!!! 100PTS!!!
Lostsunrise [7]

Answer:

x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}

Step-by-step explanation:

<u>Given functions</u>:

  p(x)=2x-4

  r(x)=\dfrac{6x-1}{9x+1}

Solve for p(x) = r(x):

\begin{aligned}p(x) & = r(x)\\\implies 2x-4 & = \dfrac{6x-1}{9x+1}\\(2x-4)(9x+1)&=6x-1\\18x^2+2x-36x-4&=6x-1\\18x^2-40x-3&=0\end{aligned}

As the found quadratic equation cannot be factored, use the Quadratic Formula to solve for x:

<u>Quadratic Formula</u>

x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0

Therefore:

a=18, \quad b=-40, \quad c=-3

Substitute the values of a, b and c into the <u>quadratic formula</u> and solve for x:

\begin{aligned}\implies x & =\dfrac{-(-40) \pm \sqrt{(-40)^2-4(18)(-3)} }{2(18)}\\\\& =\dfrac{40 \pm \sqrt{1816}}{36}\\\\& =\dfrac{40 \pm \sqrt{4 \cdot 454}}{36}\\\\& =\dfrac{40 \pm \sqrt{4}\sqrt{454}}{36}\\\\& =\dfrac{40 \pm2\sqrt{454}}{36}\\\\& =\dfrac{20 \pm\sqrt{454}}{18}\end{aligned}

Therefore, the solutions are:

x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}

Learn more about quadratic equations here:

brainly.com/question/27750885

brainly.com/question/27739892

6 0
2 years ago
Friday night 289
PIT_PIT [208]
412 + 162 + 347 = 921. Because it is closer to 900 than 1,000, the answer is 900.
7 0
3 years ago
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