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2 years ago

what is the equation of the line that is perpendicular to the line y=3/5x+10 and passes through the point (15,-5)

Mathematics

1 answer:

riadik2000 [5.3K]2 years ago

6 0

Answer:

$y = -\frac53x + 20$

Step-by-step explanation:

Hello!

A line that is perpendicular to another has an opposite-reciprocal slope.

Meaning:

Flip the sign (+/-)
Flip the fraction

The slope perpendicular to 3/5 would be -5/3.

We can solve for the y-intercept by plugging in the x and y values given from the coordinate into the equation with out new slope.

<h3 /><h3>Solve for B</h3>

$y = -\frac53x + b$
$-5 = -\frac53(15) + b$
$-5 = -25 + b$
$20 = b$

The y-intercept of the new line is 20.

The equation is $y = -\frac53x + 20$

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