Write an expression that represents the quantity 5 more than a number

Joyce paid $220 for an item at the store that was 35 percent of the original price. What was the original price?

allochka39001 [22]

Answer:

The original price of item was $ 628.57

Step-by-step explanation:

Given as :

The amount paid fro an item = $ 220

And The paid amount was 35 % of the original price

Let The original price be x

So, According to question ,

35% of original price = $ 220

Or, 35% of x = $ 220

Or, x = $\frac{220\times 100}{35}$

Or, x = $ 628.57

Hence The original price of item was $ 628.57 Answer

8 0

3 years ago

Please help i can't figure this problem out

densk [106]

Answer:

there is a very good pdf that could help you with your math problems.

8 0

2 years ago

A magazine provided results from a poll of 500500 adults who were asked to identify their favorite pie. Among the 500500 respon

Komok [63]

Answer:

99% confidence interval is wider as compared to the 80% confidence interval.

Step-by-step explanation:

We are given that a magazine provided results from a poll of 500 adults who were asked to identify their favorite pie.

Among the 500 respondents, 14% chose chocolate pie, and the margin of error was given as plus or minus ±3 percentage points.

The pivotal quantity for the confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of adults who chose chocolate pie = 14%

n = sample of adults = 500

p = true proportion

Now, the 99% confidence interval for p = $\hat p \pm Z_(_\frac{\alpha}{2}_) \times \sqrt{\frac{\hat p(1-\hat p)}{n} }$

Here, $\alpha$ = 1% so $(\frac{\alpha}{2})$ = 0.5%. So, the critical value of z at 0.5% significance level is 2.5758.

Also, Margin of error = $Z_(_\frac{\alpha}{2}_) \times \sqrt{\frac{\hat p(1-\hat p)}{n} }$ = 0.03 for 99% interval.

So, 99% confidence interval for p = $0.14 \pm2.5758 \times \sqrt{\frac{0.14(1-0.14)}{500} }$

= [0.14 - 0.03 , 0.14 + 0.03]

= [0.11 , 0.17]

Similarly, 80% confidence interval for p = $0.14 \pm 1.2816 \times \sqrt{\frac{0.14(1-0.14)}{500} }$

Here, $\alpha$ = 20% so $(\frac{\alpha}{2})$ = 10%. So, the critical value of z at 10% significance level is 1.2816.

Also, Margin of error = $Z_(_\frac{\alpha}{2}_) \times \sqrt{\frac{\hat p(1-\hat p)}{n} }$ = 0.02 for 80% interval.

So, 80% confidence interval for p = [0.14 - 0.02 , 0.14 + 0.02]

= [0.12 , 0.16]

Now, as we can clearly see that 99% confidence interval is wider as compared to 80% confidence interval. This is because more the confidence level wider is the confidence interval and we are more confident about true population parameter.

5 0

3 years ago

HELP PLEASEEEEE Combine like terms to simplify the expression: 1.17-0.07a+(-3.92a)

chubhunter [2.5K]

Answer: hope this helps

Step-by-step explanation:

Simplifying

1.17 + -0.07a + (-3.92a) = 0

Combine like terms: -0.07a + (-3.92a) = -3.99a

1.17 + -3.99a = 0

Solving

1.17 + -3.99a = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-1.17' to each side of the equation.

1.17 + -1.17 + -3.99a = 0 + -1.17

Combine like terms: 1.17 + -1.17 = 0.00

0.00 + -3.99a = 0 + -1.17

-3.99a = 0 + -1.17

Combine like terms: 0 + -1.17 = -1.17

-3.99a = -1.17

Divide each side by '-3.99'.

a = 0.2932330827

Simplifying

a = 0.2932330827

6 0

3 years ago

T-8 in a algebric expression

jeka57 [31]

Answer:

the answer would be 7x-8. i hope this helped. :).

Step-by-step explanation:

yepppp

7 0

3 years ago