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Fantom [35]
3 years ago
9

Which graph represents the solution set of this inequality?

Mathematics
1 answer:
Temka [501]3 years ago
7 0

Answer:

to graph an inequality you need a variable. please rewrite your question.

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Is (3x+1)(4x-5) the factor form of 12x^2-11x-5?
arsen [322]

Answer:

Yes

Step-by-step explanation:

using distributive properties,

(3x+1)(4x-5) = 3x(4x-5) + 1(4x-5)

=> 12x^2 - 15x +4x - 5

=> 12x^2 - 11x - 5

6 0
3 years ago
Given a normal distribution with a mean of 125 and a standard deviation of 14, what percentage of values is within the interval
Anit [1.1K]

Answer:68%

Step-by-step explanation:

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7 0
4 years ago
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Write the trinomial as a square of a binomial or as an expression opposite to a square
timurjin [86]
(3a-7)^2

1. 9a^2-21a-21a+49
2. 3a(3a-7)-7(3a-7)
3. (3a-7)(3a-7)
4. Combine like terms
3 0
2 years ago
Why do the functions f(x) = sin−1(x) and g(x) = cos−1(x) have different ranges?
Gnom [1K]
We Know that
For a function to have an inverse function, it must be one-to-one—that is, it must pass the Horizontal Line Test.

1. On the interval [–pi/2, pi/2], the function y = sin x is increasing
2. On the interval [–pi/2, pi/2], y = sin x takes on its full range of values, [–1, 1]
3. On the interval [–pi/2, pi/2], y = sin x is one-to-one
sin x has an inverse function on this interval [–pi/2, pi/2]

On the restricted domain [–pi/2, pi/2]  y = sin x has a unique inverse function called the inverse sine function. <span>f(x) = sin−1(x)
</span>the range of y=sin x  in the domain [–pi/2, pi/2]  is [-1,1] 
the range of y=sin-1  x  in the domain [-1,1]  is [–pi/2, pi/2]  

1. On the interval [0, pi], the function y = cos x is decreasing
2. On the interval [0, pi], y = cos x takes on its full range of values, [–1, 1]
3. On the interval [0, pi], y = cos x is one-to-one
cos x has an inverse function on this interval [0, pi]

On the restricted domain [0, pi]  y = cos x has a unique inverse function called the inverse sine function. f(x) = cos−1(x)
the range of y=cos x  in the domain [0, pi]  is [-1,1] 
the range of y=cos-1  x  in the domain [-1,1]  is [0, pi] 

the answer is

<span>the values ​​of the range are different because the domain in which the inverse function exists are different</span>  
8 0
3 years ago
Brainly for step by step correct answer ❤️
Alik [6]
Take the radius squared 10*10=100 then times that by pi which equals 314 then by 16 which is 5,024 then multiply that by 75 and get 376,800
3 0
3 years ago
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