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1 year ago

Write the prime for factorization of 4

Mathematics

1 answer:

faust18 [17]1 year ago

4 0

Answer:

2×2 mark me brainlist

4
divided by 2
2×2

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A diameter of the sphere is MT CT CD

iren2701 [21]

Answer:

Step-by-step explanation:

The diameter is the longest possible line through the sphere and passes through the center.

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3 years ago

Find the Area. Use 3.14 for Pi. Label your answer with ft2.

aivan3 [116]

Answer:

133.04ft²

Step-by-step explanation:

Area of a circle is:

$A=\pi r^2\\\\r - \text{Radius.}$

We are given the diameter. The radius of the given circle is 6. Note that the diameter is twice the radius.

Using 3.14 for pi:

$A=3.14(6)^2\\\\A=3.14*36\\\\A\text{ } $$\approx$$\text{ }113.04$

The area is appropriately 133.04ft².

Hope this helps.

8 0

2 years ago

Read 2 more answers

What is the solution to the equation 38x=10x+42

Alex

hey mate here is you answer..! ;)

Answer:

x = 3/2

Step-by-step explanation:

38x = 10x + 42

=>38x - 10x = 42

=>28x = 42

=>x = 3/2

8 0

3 years ago

Determine if the columns of the matrix form a linearly independent set. Justify your answer. [Start 3 By 4 Matrix 1st Row 1st Co

Volgvan

Answer:

Linearly Dependent for not all scalars are null.

Step-by-step explanation:

Hi there!

1)When we have vectors like $v_{1},v_{2},v_{3}, ...$ we call them linearly dependent if we have scalars $a_{1},a_{2},a_{3},...$ as scalar coefficients of those vectors, and not all are null and their sum is equal to zero.

$a_{1}\vec{v_{1}}+a_{2}\vec{v_{2}}+a_{3}\vec{v_{3}}+...a_{m}\vec{v_{m}}=0$

When all scalar coefficients are equal to zero, we can call them linearly independent

2) Now let's examine the Matrix given:

$\begin{bmatrix}1 &-2 &2 &3 \\ -2 & 4 & -4 &3 \\ 0&1 &-1 & 4\end{bmatrix}$

So each column of this Matrix is a vector. So we can write them as:

$\vec{v_{1}}=\left \langle 1,-2,1 \right \rangle,\vec{v_{2}}=\left \langle -2,4,-1 \right \rangle,\vec{v_{3}}=\left \langle 2,-4,4 \right \rangle\vec{v_{4}}=\left \langle 3,3,4 \right \rangle$ Or

Now let's rewrite it as a system of equations:

$a_{1}\begin{bmatrix}1\\ -2\\ 0\end{bmatrix}+a_{2}\begin{bmatrix}-2\\ 4\\ 1\end{bmatrix}+a_{3}\begin{bmatrix}2\\ -4\\ -1\end{bmatrix}+a_{4}\begin{bmatrix}3\\ 3\\ 4\end{bmatrix}=\begin{bmatrix}0\\ 0\\ 0\end{bmatrix}$

2.1) Since we want to try whether they are linearly independent, or dependent we'll rewrite as a Linear system so that we can find their scalar coefficients, whether all or not all are null.

Using the Gaussian Elimination Method, augmenting the matrix, then proceeding the calculations, we can see that not all scalars are equal to zero. Then it is Linearly Dependent.

$\left ( \left.\begin{matrix}1 &-2 &2 &3 \\ -2 &4 &-4 &3 \\ 0 & 1 &-1 &4 \\ \end{matrix}\right|\begin{matrix}0\\ 0\\ 0\end{matrix} \right )R_{1}\times2 +R_{2}\rightarrow R_{2}\left ( \left.\begin{matrix}1 &-2 &2 &3 \\ 0 &0 &9 &0\\ 0 & 1 &-1 &4 \\ \end{matrix}\right|\begin{matrix}0\\ 0\\ 0\end{matrix} \right )\ R_{2}\Leftrightarrow R_{3}\left ( \left.\begin{matrix}1 &-2 &2 &3 \\ 0 &1 &-1 &4 \\ 0 &0 &9 &0 \\ \end{matrix}\right|\begin{matrix}0\\ 0\\ 0\end{matrix} \right )$ $\left\{\begin{matrix}1a_{1} &-2a_{2} &+2a_{3} &+3a_{4} &=0 \\ &1a_{2} &-1a_{3} &+4a_{4} &=0 \\ & & &9a_{4} &=0 \end{matrix}\right.\Rightarrow a_{1}=0, a_{2}=a_{3},a_{4}=0$

$S=\begin{bmatrix}0\\ a_{3}\\ a_{3}\\ 0\end{bmatrix}$

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3 years ago

Jason wears a size 10 shoe, Donal wears a size 9, and Mishka wears a size 11. What is their average shoe size?

olya-2409 [2.1K]

9 bc you can add all the numbers together then divide that by the total amount of numbers there were

7 0

2 years ago

Read 2 more answers