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Nookie1986 [14]
3 years ago
14

Suppose y varies directly with x. Write a direct variation equation that relates x and y when y = 12 and x = 24.

Mathematics
1 answer:
AfilCa [17]3 years ago
4 0

Answer:

20

Step-by-step explanation:

x = 20.

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Your class has 26 students, which represents 5% of your school's enrollment. Your friend uses the proportion 5/100 =n/26 to find
dedylja [7]
26 is a part of the whole. the proportion should be set up:

(26/x) = (5/100) It's the overall enrollment that is being asked.

If you also need to solve: Cross multiply, 26(100) = 5x, 2600 = 5x, divide both sides by 5, 520 is the enrollment
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What is the distance between -2/3 and 4/3 on a number line?
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3 years ago
What's 1.8499 x 10^9 in standard notation
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5 0
3 years ago
When the sum of \, 528 \, and three times a positive number is subtracted from the square of the number, the result is \, 120. F
aleksandr82 [10.1K]

Let x be the unknown number. So, three times that number means 3x, and the square of the number is x^2

We have to sum 528 and three times the number, so we have 528+3x

Then, we have to subtract this number from x^2, so we have

x^2-(3x+528)

The result is 120, so the equation is

x^2 - 3x - 528 = 120 \iff x^2 - 3x - 648 = 0

This is a quadratic equation, i.e. an equation like ax^2+bx+c=0. These equation can be solved - assuming they have a solution - with the following formula

x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

If you plug the values from your equation, you have

x_{1,2} = \dfrac{3\pm\sqrt{9-4\cdot(-648)}}{2} = \dfrac{3\pm\sqrt{9+2592}}{2} = \dfrac{3\pm\sqrt{2601}}{2} = \dfrac{3\pm51}{2}

So, the two solutions would be

x = \dfrac{3+51}{2} = \dfrac{54}{2} = 27

x = \dfrac{3-51}{2} = \dfrac{-48}{2} = -24

But we know that x is positive, so we only accept the solution x = 27

6 0
3 years ago
HELP ME PLEASEEEEEEEEEEEEEEEEEEEEEEEEEE WILL GIVE BRAINLIST
Nadya [2.5K]

Answer:

width = 18 cm

27/3.6=7.5

2.4x7.5=18

4 0
3 years ago
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