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aivan3 [116]
3 years ago
9

Which element has the following noble gas configuration:

Chemistry
1 answer:
aniked [119]3 years ago
8 0
Einsteinium Would be your correct Answer.The electron Configuration [Ra] 7s2 5f8 is Not Valid because Ra is basically 7s2. However, you have Ra 7s2 5f8. You can never repeat an electron.
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Its D. 13-14 billion years
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Which statement best describes why radioactive atoms can be used to date materials?
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The molar solubility of cui is 2. 26 × 10-6 m in pure water. Calculate the ksp for cui.
nataly862011 [7]

Ksp(the solubility product constant) = [Cu⁺] [I⁻]

So, the Ksp for Cui would be:

Ksp = (2.26 × 10⁻⁶) (2.26 × 10⁻⁶) = 5.11 x 10⁻¹²

<h3 />

Formula used:

K = K_{sp} = [A^+]^a [B^-]^b, where

Ksp = solubility product constant

A⁺    = cation in an aquious solution

B⁻ = anion in an aqueous solution

a, b = relative concentrations of a and b

<h3><u>Definition</u></h3>

The equilibrium constant for a solid material dissolving in an aqueous solution is the SOLUBILITY PRODUCT CONSTANT, Ksp. It stands for the degree of solute dissolution in solution. A substance's Ksp value increases with how soluble it is.

Take into account the general dissolving response (in aqueous solutions) below:

                           aA(s)⇔cC(aq)+dD(aq)

The molarities or concentrations of the products (cC and dD) must be multiplied in order to find the Ksp. Any product that has a coefficient in front of it must be raised to the power of that coefficient (and also multiply the concentration by that coefficient).

Learn more about the concept of Ksp through the link:

brainly.com/question/1419865

#SPJ4

7 0
1 year ago
Liquid sodium is being considered as an engine coolant. How many grams of liquid sodium (minimum) are needed to absorb 8.60 MJ o
Alecsey [184]

Answer: 64.216\times 10^4grams of liquid sodium is required.

Explanation: To calculate the mass of liquid sodium, we use the formula:

q=nc\Delta T\\q=\frac{m}{M}c\Delta T

where,

q = heat required, 8.60MJ=8.60\times 10^6J   (Conversion factor: 1MJ = 1000000J)

m = Mass of liquid sodium, ?g

M = Molar mass of liquid sodium, 23g/mol

c = Specific heat capacity, 30.8J/Kmol

\Delta T = change in temperature,  \Delta T=(510-500)K=10K    (Conversion factor: 0°C = 273K)

Putting values in above equation, we get:

8.60\times 10^6J=\frac{m}{23g/mol}\times 30.8J/Kmol\times 10K

m=64.216\times 10^4grams

5 0
3 years ago
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