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aivan3 [116]
3 years ago
9

Which element has the following noble gas configuration:

Chemistry
1 answer:
aniked [119]3 years ago
8 0
Einsteinium Would be your correct Answer.The electron Configuration [Ra] 7s2 5f8 is Not Valid because Ra is basically 7s2. However, you have Ra 7s2 5f8. You can never repeat an electron.
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Earth's first semi-permanent atmosphere consisted of abundant water vapor, carbon dioxide, nitrogen, ammonia, and traces of meth
statuscvo [17]
Organic compounds from the Cambrian era
7 0
3 years ago
What volume of ammonia in liters, at STP, can be produced from 2.0 kg of hydrogen gas, H2, and an excess of nitrogen gas, N2? N2
Sonbull [250]
Ok so rewrite the equation for yourself :).

N2 + 3H2 -> 2NH3 (Always check if it is balanced).

Ok so we have 2kg of hydrogen conver this to grams and then to moles.
2kg -> 2000g
2000g divide by R.M.M of H2
R.M.M
2H - 2 * 1 -> 2
2000/2 - 1000 moles.
Look at the ratio of H2 to 2NH3.
We see that we get 2NH3 for every H2 therefore the ratio is 1:2.
This means that we HAVE 2000 moles of 2NH3.
At stp. we know that 1 moles = 22.4 Litres
We have 2000 moles that means that we produce 44800 litres of NH3 at stp.
2000 * 22.4 - 44800
Hope this helps :).

4 0
3 years ago
In the uncatalyzed reaction N2O4 (g) ⇌ 2 NO2 (g) the pressure of the gases at equilibrium are PN2O4 = 0.377 atm and PNO2 = 1.56
larisa86 [58]

Answer:

The pressures will remain at the same value.

Explanation:

A catalyst is a substance that alter the rate of a chemical reaction. It either speeds up the or slows down the rate of a chemical reaction.

While a catalyst affects the rate, it is noteworthy that it has no effect on the equilibrium position of the chemical reaction. A catalyst works by creating an alternative pathway for the reaction to proceed. Most times, it decreases the activation energy needed to kickstart the chemical reaction.

Hence, we know that it has no effect on the equilibrium position. Factors affecting equilibrium position includes, temperature and concentration of reactants and products( pressure in terms of gases).

The reactants and the products here are gaseous, and as such pressure affects the equilibrium position. Now, we have established that the equilibrium position is unaffected. And as such the pressure affecting it does not change.

Thus, we have established that the pressure of the products and reactants are unaffected and as such they remain at their value unaffected.

8 0
4 years ago
AIDS is one disease caused by a virus infection. The virus attacks immune system cells known as T cells.
VLD [36.1K]

Answer:

yes,its true

Explanation:

I just want to say first off

the immune cell known as T cell also known as white blood cells

Since the first main attack from the bodies response against a virus is deploying T cells to attack

CD4 cells are the basic T cells and HIV virus which is AIDS will start to "Eat itself inside" Ofc not they will use protein spikes to form their way in

they start to create copies of themselves inside the T cell itself and creating a new protein called Env to form their ways in ofc

They are able to bypass CD4 cells is because its a basic cellular receptor for T cells making them really deadly

They now will start to attack other white cells and deploying more and more of their virus cells

7 0
3 years ago
Given the enthalpies of reaction
Tju [1.3M]

2SO₂+O₂⇒2SO₃  ΔH=-197 kJ

<h3>Further explanation</h3>

Based on the principle of Hess's Law, the change in enthalpy of a reaction will be the same even though it is through several stages or ways

Reaction

2SO₂+O₂⇒2SO₃

Given :

1. S(s)+O₂(g)→SO₂(g) ΔH = -297 kJ

Reverse

SO₂(g) ⇒S(s)+O₂(g ΔH = +297 kJ (sign change to +) x 2

2SO₂(g) ⇒2S(s)+2O₂(g ΔH =  +594 kJ

2.2S(s)+3O2(g)→2SO3(g) ΔH=-791kJ

Add both reactions and remove/subtract the same compound for different sides

1. 2SO₂(g) ⇒2S(s)+2O₂(g) ΔH =  +594 kJ

2.2S(s)+3O₂(g)→2SO₃(g) ΔH=-791kJ

--------------------------------------------------------+

2SO₂+O₂⇒2SO₃  ΔH=-197 kJ

5 0
3 years ago
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