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Alexxx [7]
3 years ago
15

What is solution, colloid, suspension?​

Chemistry
2 answers:
Archy [21]3 years ago
7 0
<h3><em><u>Suspensions and colloids are heterogeneous mixtures. A suspension is identifiable because its particles are large and settle out of the dispersing medium due to the effects of gravity. The dispersed particles of a colloid are intermediate in size between those of a solution and a suspension.</u></em></h3><h2><em><u>Above</u></em><em><u> </u></em><em><u>ans</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>correct</u></em><em><u> </u></em><em><u> </u></em><em><u>mark</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>as</u></em><em><u> </u></em><em><u>brainliest</u></em><em><u> </u></em><em><u>ans</u></em></h2>

Iteru [2.4K]3 years ago
3 0

Explanation:

<h2><em><u>SOLUTION</u></em><em><u>:</u></em></h2>

<em>Solution is a homogenous mixture of two or more substances in relative amounts that can be varied continuously up to what is called the limit of solubility. </em>

<h2><em><u>COLLOID</u></em><em><u>:</u></em></h2>

<em>A mixture in which one substance is divided into minute particles (called colloidal particles) and dispersed throughout a second substance</em>

<h2><em><u>SUSPEN</u></em><em><u>SION</u></em><em><u>:</u></em></h2>

<em>A suspension is a heterogeneous mixture of a finely distributed solid in a liquid. The solid is not dissolved in the liquid, as is the case with a mixture of salt and water. </em>

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A concentration cell is constructed using two Ni electrodes with Ni2+ concentrations of 1.0 M and 1.00 � 10�4 M in the two half-
Komok [63]

<u>Answer:</u> The cell potential of the cell is +0.118 V

<u>Explanation:</u>

The half reactions for the cell is:

<u>Oxidation half reaction (anode):</u>  Ni(s)\rightarrow Ni^{2+}+2e^-

<u>Reduction half reaction (cathode):</u>  Ni^{2+}+2e^-\rightarrow Ni(s)

In this case, the cathode and anode both are same. So, E^o_{cell} will be equal to zero.

To calculate cell potential of the cell, we use the equation given by Nernst, which is:

E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Ni^{2+}_{diluted}]}{[Ni^{2+}_{concentrated}]}

where,

n = number of electrons in oxidation-reduction reaction = 2

E_{cell} = ?

[Ni^{2+}_{diluted}] = 1.00\times 10^{-4}M

[Ni^{2+}_{concentrated}] = 1.0 M

Putting values in above equation, we get:

E_{cell}=0-\frac{0.0592}{2}\log \frac{1.00\times 10^{-4}M}{1.0M}

E_{cell}=0.118V

Hence, the cell potential of the cell is +0.118 V

5 0
3 years ago
Explain why it is important that a chemical equation be balanced
skad [1K]
In order to follow the law of conservation of mass, each side must contain an equal amount of each atom
6 0
4 years ago
Is air a mixture give 3 reasons
solmaris [256]

Answer: https://van.physics.illinois.edu/qa/listing.php?id=1508&t=why-is-air-a-mixture

Explanation: The best reason I can think of for why we believe that air is a mixture is that freezing air slowly yields different liquids at different temperatures. Liquid nitrogen has a different boiling point than liquid oxygen. They also freeze at different temperatures. If air were only 1 compound, then air in its entirety would have a single boiling point and a single freezing point.  

Jason (w. mike)

air is not a mixture because of scientists freezing it and finding different liquids, it is a mixture because the compounds that make up air e.g. oxygen (o2), Carbon dioxide (co2) and the most important Nitrogen which is an element and makes up 78.09% of air are not chemically bound in the way that compounds are because they can be separated easily and there has been no change in state to any of the compounds or elements in air

6 0
3 years ago
When solid calcium carbonate is heated, it decomposes according to the reaction: CaCO3(s) ⇄ CaO(s) + CO2(g) Kp = 0.50 A sample o
blagie [28]

Explanation:

Relation between K_{p} and K_{c} is as follows.

            K_{p} = K_{c} [RT]^{\Delta n}

Given,   temperature = 830^{o}C = (830 + 273) K = 1103 K

            R = 8.314 J/mol K

       \Delta n = 1 - 0 = 1

Now, putting the given values into the above formula as follows.

              K_{p} = K_{c} [RT]^{\Delta n}

                 0.5 = K_{c} \times (8.314 \times 1103)^{1}

                     K_{c} = 5.452 \times 10^{-3}

ICE table for the given reaction will be as follows.

                  CaCO_{3}(s) \rightleftharpoons CaO(s) + CO_{2}(g)

Initial:           c                        -          -  

Equilibrium:  (c - x)               x         x

       K_{c} = [CO_{2}]

          5.452 \times 10^{-3} = x

Hence, same amount of CaO is produced.

Moles of CaO = 5.452 \times 10^{-3}

    Mass of CaO = 5.452 \times 10^{-3} \times 57 g/mol

                          = 0.310 g

Thus, we can conclude that 0.310 g of CaO produced when equilibrium is established.

8 0
3 years ago
What mass of sodium chloride is needed to prepare 200 ml of a 0.1 M solution
Nikolay [14]

Answer:

C. 1.17 grams

Explanation:

  • The molarity is the no. of moles of solute in a 1.0 L of the solution.

<em>M = (mass/molar mass)solute x (1000/ V)</em>

M = 0.1 M, mass = ??? g, molar mass of NaCl = 58.44 g/mol, V = 200.0 mL.

∴ mass of NaCl = (M)(molar mass)(V)/1000 = (0.1 M)(58.44 g/mol)(200.0 mL)/1000 = 1.168 g ≅ 1.17 g.

5 0
3 years ago
Read 2 more answers
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