Salt water, since it is no longer a pure substance :)
Answer:
4.8 g/mL is the density of chloroform vapor at 1.00 atm and 298 K.
Explanation:
By ideal gas equation:
Number of moles (n)
can be written as: 
where, m = given mass
M = molar mass
where,
which is known as density of the gas
The relation becomes:
.....(1)
We are given:
M = molar mass of chloroform= 119.5 g/mol
R = Gas constant = 
T = temperature of the gas = 
P = pressure of the gas = 1.00 atm
Putting values in equation 1, we get:
4.8 g/mL is the density of chloroform vapor at 1.00 atm and 298 K.
Answer:
apc
Explanation:
anaphase-promoting complex,
Answer
27.7 moles
Explanation:
Data Given:
Chemical formula of Calcium carbonate = CaCO₃
no. of atoms of CaCO₃ = 8.35 x 10²⁵ atoms
moles of CaCO₃= ?
Solution
First convert number of atoms to number of molecules
As
we have 5 atoms per molecule then how many molecules will be for 8.35 x 10²⁵ atoms
So, apply unity formula
5 atoms ≅ 1 molecule of CaCO₃
8.35 x 10²⁵ atoms ≅ X molecule of CaCO₃
by doing cross multiplication
X molecule of CaCO₃ = 8.35 x 10²⁵ atoms x 1 molecule / 5 atoms
X molecule of CaCO₃ = 1.67 x 10²⁵ molecule
Formula will be used
no. of moles = no. of molecules / Avogadro's number . . . . (1)
Where
Avogadro's number = 6.022 x 10²³ molecules/mol
So,
Put values in equation 1
no. of mole = 1.67 x 10²⁵/ 6.022 x 10²³ (molecules/mol)
no. of mole = 27.7 moles
So,
moles of CaCO₃ = 27.7 moles
