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Answer:
13 mol NO
Explanation:
Step 1: Write the balanced equation
4 NH₃(g) + 5 O₂(g) ⇒ 4 NO(g) + 6 H₂O(g)
Step 2: Establish the appropriate molar ratio
According to the balanced equation, the molar ratio of O₂ to NO is 5:4.
Step 3: Calculate the number of moles of O₂ needed to produce 16 moles of NO
We will use the previously established molar ratio.
16 mol O₂ × 4 mol NO/5 mol O₂ = 13 mol NO
As Density = Mass/Volume
Mass = 26.0g
Density = 1.44g/mL
Therefore Volume = Mass/Density
=> Volume = 26.0/1.44 = 18.055... = 18.1mL (to 3 sig figs)
